Rubina11 wrote:
A class collects $50 to buy flowers for a classmate who is in the hospital. Roses cost $3 each, and carnations cost $2 each. No other flowers are to be used. How many different bouquets could be purchased for exactly $50?
(A) 1 (B) 7 (C) 9 (D) 16 (E) 17
As $50 is divisible by $2 so let's start with all C flowers.
25C * $2= $50
With $50, we can have maximum 16R ($3*16= $48) + 1C ($2*1=$2)
Gradually, ............................... 14R ($3*14= $42) + 4C ($2*4=$8)
12R ($3*12= $36) + 7C ($2*7=$14)
10R ($3*10= $30) + 10C ($2*10=$20)
8R ($3*8= $24) + 13C ($2*13=$26)
6R ($3*6= $18) + 16C ($2*16=$32)
4R ($3*4= $12) + 19C ($2*19=$38)
2R ($3*2= $6) + 22C ($2*22=$44) ;
TOTAL 9 Possibilities.
Any shortcut or easier way to solve this kinda problem ? Thanks