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# a club has 8 male and 8 female members. the club is choosing

Author Message
VP
Joined: 30 Sep 2004
Posts: 1425
Location: Germany

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07 Mar 2005, 08:45
Rupstar wrote:
banerjeea_98 wrote:
there is only 1 way to choose both Rob and Ann and then 7C2*7C2 ways to choose for the rest of the 4 positions.

wouldnt there be two ways to choose rob and ann first rob then ann and ann then rob?
so shouldnt it be 2*7C2*7C2?

...order does not matter, so rob ann and ann rob is the same !
VP
Joined: 18 Nov 2004
Posts: 1374

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08 Mar 2005, 08:19
HongHu wrote:
Nobody had given this one any more thoughts?

yes, my approach for the first q is wrong, we r counting dups in that scenario I believe.
Manager
Joined: 11 Jan 2005
Posts: 54
Location: Mexico City

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14 Mar 2005, 15:59
how are we counting duplicates in 8c2*8c2*12c2

how do we remove the duplicates?
Non-Human User
Joined: 09 Sep 2013
Posts: 9415
Re: a club has 8 male and 8 female members. the club is choosing  [#permalink]

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14 May 2018, 05:35
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: a club has 8 male and 8 female members. the club is choosing &nbs [#permalink] 14 May 2018, 05:35

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