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Re: A one-foot stick is marked in 1/6 and 1/8 portion. [#permalink]
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Raihanuddin wrote:
A one-foot stick is marked in 1/6 and 1/8 portion. How many total markings will there be, including the end points?


There is always an easy approach for this type of sums

Multiply the denominator = 6*8 =48. Say there are 48 numbers
Marking with 6 = 8 markings
Marking with 8 = 6 markings
Here notice that we are marking 24(L.C.M of 6 and 8) and 48 twice. So subtract 2 from (8+6=14)
Total markings = 14-2 = 12+1 =13

Why are we adding 1? Because when we mark we don't consider the starting point. So we have to put a mark there.
By visualizing we can find that we normally don't put mark at the beginning of marking the sticks


You could use 24 instead of 48. Think it would be easier.
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Re: A one-foot stick is marked in 1/6 and 1/8 portion. [#permalink]
Raihanuddin wrote:
A one-foot stick is marked in 1/6 and 1/8 portion. How many total markings will there be, including the end points?
a. 16
b. 15
c. 14
d. 13
e. 12



LCM of 6 & 8 = 24

1/6 marking are (Table of 4) 0...... 4 ........... 8.......... 12 .......... 16 ........... 20 ............ 24 (Total = 7)

1/8 marking are (Table of 3) 0 ....... 3 ...... 6...... 9........ 12......... 15......... 18......... 21.......... 24 (Total = 9)

Overlapping markings are 0 ........ 12 ......... 24 (Total = 3)

Total markings = 7+9-3 = 13

Answer = D
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Re: A one-foot stick is marked in 1/6 and 1/8 portion. [#permalink]
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Thank you Bunuel
Yes I could but sometimes it becomes harder to visualize. Sometimes, we become confuse to use table of 4 in 1/6 portion and table of 3 in 1/8 portion as Paresh has shown. So I thought multiplication may help me in this case to visualize.
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Re: A one-foot stick is marked in 1/6 and 1/8 portion. [#permalink]
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Re: A one-foot stick is marked in 1/6 and 1/8 portion. [#permalink]
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