Bunuel wrote:

Tough and Tricky questions: Word Problems.

A total of 9 women and 12 men reside in the 21 apartments that are in a certain apartment building, one person to each apartment. If a poll taker is to select one of the apartments at random, what is the probability that the resident of the apartment selected will be a woman who is a student?

(1) Of the women, 4 are students.

(2) Of the women, 5 are not students.

Kudos for a correct solution.Total Residents =21

No. of Women = 9

Let X be the no of women who are students.

Probability to select Woman P (Woman) = \(\frac{9}{12}\)

Probability of getting a Women who is student = \(\frac{P(Women)*X}{9}\)

P(WomanStudent) = \(\frac{9}{21}*\frac{X}{9}\)

P(WomanStudent) = X/21

Now X we can find from both statement 1 and 2 seperately

Therefore

Option D
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Regards ,

Dhruv

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