tparanidharan wrote:
A train X starts from Meerut at 4 P.M. and reaches Ghaziabad at 5 P.M. while
another train Y starts from Ghaziabad at 4 P.M. and reaches Meerut, at 5.30 PM. At what time the two trains meet each other.
.
Sol:
Let the distance between two points be "D miles"
Speed of X = D/1= D miles/h
Speed of Y = D/1.5= 2D/3 miles/h
Suppose X meets Y after completing "x miles" traveling for \(t_x\) hours and y traveled \(t_y\) hours
\(t_x=t_y\)
\(time=\frac{Distance}{Speed}\)
\(\frac{x}{D}=\frac{3(D-x)}{2D}\)
\(2x=3(D-x)\)
\(5x=3D\)
\(x=\frac{3}{5}D\)
Now,
x travels D miles in 1 hour
To travel (3/5)D miles, it would need 3/5 hours = 36minutes.
Thus; the trains meet at 4:36PM.
_________________
~fluke
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