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An integer x divided by nine gives a number f, where 0<f<1. What is th

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An integer x divided by nine gives a number f, where 0<f<1. What is th  [#permalink]

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New post 19 Aug 2018, 01:06
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A
B
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D
E

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  65% (hard)

Question Stats:

50% (01:58) correct 50% (01:38) wrong based on 37 sessions

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An integer x divided by nine gives a number f, where 0<f<1. What is the value of x?

(1) x is not a prime number.

(2) 2x has less than 3 factors.
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Re: An integer x divided by nine gives a number f, where 0<f<1. What is th  [#permalink]

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New post 19 Aug 2018, 04:47
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blueviper wrote:
An integer x divided by nine gives a number f, where 0<f<1. What is the value of x?

(1) x is not a prime number.

(2) 2x has less than 3 factors.


Given, \(\frac{x}{9}=f\), where 0<f<1
This hold when x is less than 9 and x is a positive integer.
So, possible integer values of x: 1,2,3,4,5,6,7,8

St1:- x is not a prime number.
So, discard 2,3,5,and 7.
Possible values of x: 1,4,6, and 8
No unique value of x.
Therefore, insufficient.

St2:- 2x has less than 3 factors
2x: 1*2,2*2,3*2,4*2,5*2,6*2,7*2,8*2

Only 2 has two factors, viz, 1 &2 at x=1.

We have obtained an unique value of x,

Therefore, sufficient.

Ans. (B)
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Re: An integer x divided by nine gives a number f, where 0<f<1. What is th   [#permalink] 19 Aug 2018, 04:47
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