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anybody has a quick approach to this one for the value of N:

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Director
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anybody has a quick approach to this one for the value of N: [#permalink]

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New post 22 Apr 2007, 11:33
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anybody has a quick approach to this one for the value of N:

|NтАУ|N+1||=|NтАУ2|

Kudos [?]: 162 [1], given: 0

SVP
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 [#permalink]

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New post 22 Apr 2007, 12:53
o If n+1 >= 0, then
|NтАУ|N+1||=|NтАУ2|
<=> |N - N -1| = |N-2|
<=> 1 = |N-2|
<=> N=3 or N = 1

o If n+1 =< 0, then
|NтАУ|N+1||=|NтАУ2|
<=> |N + N+1| = |N-2|
<=> |2*N+1| = |N-2|
<=> -(2*N+1) = -(N-2) as 2*N+1 < 0 and N-2 < 0
<=> N = -3

Thus, N = -3 or N=1 or N=3

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SVP
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 [#permalink]

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New post 22 Apr 2007, 13:32
techjanson wrote:
Fig wrote:
o If n+1 >= 0, then
|NтАУ|N+1||=|NтАУ2|
<=> |N - N -1| = |N-2|
<=> 1 = |N-2|
<=> N=3 or N = 1

o If n+1 =< 0, then
|NтАУ|N+1||=|NтАУ2|
<=> |N + N+1| = |N-2|
<=> |2*N+1| = |N-2|
<=> -(2*N+1) = -(N-2) as 2*N+1 < 0 and N-2 < 0
<=> N = -3

Thus, N = -3 or N=1 or N=3


Excellent explanation. Thanks!


Thanks to u :)

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Current Student
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 [#permalink]

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New post 23 Apr 2007, 13:06
FIG: you are the abs, mod King :)

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Reviews Badge
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New post 23 Apr 2007, 13:19
Fig wrote:
o If n+1 >= 0, then
|NтАУ|N+1||=|NтАУ2|
<=> |N - N -1| = |N-2|
<=> 1 = |N-2|
<=> N=3 or N = 1

o If n+1 =< 0, then
|NтАУ|N+1||=|NтАУ2|
<=> |N + N+1| = |N-2|
<=> |2*N+1| = |N-2|
<=> -(2*N+1) = -(N-2) as 2*N+1 < 0 and N-2 < 0
<=> N = -3

Thus, N = -3 or N=1 or N=3


Can you please explain the step in red color?

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SVP
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 [#permalink]

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New post 23 Apr 2007, 13:25
fresinha12 wrote:
FIG: you are the abs, mod King :)


Thanks :)... I just hope it helps to clarify it :)

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 [#permalink]

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New post 23 Apr 2007, 13:28
goalsnr wrote:
Fig wrote:
o If n+1 >= 0, then
|NтАУ|N+1||=|NтАУ2|
<=> |N - N -1| = |N-2|
<=> 1 = |N-2|
<=> N=3 or N = 1

o If n+1 =< 0, then
|NтАУ|N+1||=|NтАУ2|
<=> |N + N+1| = |N-2|
<=> |2*N+1| = |N-2|
<=> -(2*N+1) = -(N-2) as 2*N+1 < 0 and N-2 < 0
<=> N = -3

Thus, N = -3 or N=1 or N=3


Can you please explain the step in red color?


Ok :)

In the second case, we have n+1 =< 0. Thus, we have |n+1| = -(n+1) : an absolute must always be positive or equal to 0. :)

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Director
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Re: PS: Mod [#permalink]

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New post 20 Apr 2009, 01:01
Himalayan wrote:
anybody has a quick approach to this one for the value of N:

|NтАУ|N+1||=|NтАУ2|


what does NтАУ and NтАУ2 mean here?

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Manager
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Schools: Kellogg (R1 Dinged),Cornell (R2), Emory(Interview Scheduled), IESE (R1 Interviewed), ISB (Interviewed), LBS (R2), Vanderbilt (R3 Interviewed)
Re: PS: Mod [#permalink]

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New post 20 Apr 2009, 12:19
same question as above

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Manager
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Re: PS: Mod [#permalink]

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New post 02 Aug 2009, 13:29
Is there a quant guru that could explain this question in more depth?

I don't understand the transition ...

"If n+1 >= 0, then
|NтАУ|N+1||=|NтАУ2|
<=> |N - N -1| = |N-2|"

Why?

Thanks in advance,
a
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Please kudos if my post helps.

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Re: PS: Mod [#permalink]

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New post 02 Aug 2009, 22:32
Himalayan wrote:
anybody has a quick approach to this one for the value of N:
|NтАУ|N+1||=|NтАУ2|


I guess the symbol (-ve sign) has been changed into something else. The question should be as under:

Quote:
What is the value of N:
|N - |N+1||=|N - 2|


Work out from the inside modulus
The possibilities for : (1) If (N+1) >= 0 (2) If (N+1) <= 0

(1) If (N+1) >= 0
|N - N -1| = |N - 2|
|-1| = |N - 2|
1 = |N - 2|
N = 1 or 3

(2) If (N+1) <= 0
|N+N+1| = |N - 2|
|2N+1| = |N - 2|

(i) 2N +1 = N - 2
2N - N = - 3
N = -3

(ii) 2N +1 = N - 2
2N +1 = - N + 2
2N + N = 1
N = 1/3

(ii) - 2N -1 = - N + 2
-N = 3
N = -3

N = -3, 1/3, 1, & 3.
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GT

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Re: PS: Mod   [#permalink] 02 Aug 2009, 22:32
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anybody has a quick approach to this one for the value of N:

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