Author 
Message 
TAGS:

Hide Tags

Intern
Joined: 24 Nov 2012
Posts: 12

At a picnic there were 3 times as many adults as children [#permalink]
Show Tags
26 Nov 2012, 21:56
2
This post received KUDOS
11
This post was BOOKMARKED
Question Stats:
67% (00:58) correct 33% (01:13) wrong based on 399 sessions
HideShow timer Statistics
At a picnic there were 3 times as many adults as children and twice as many women as men. If there was a total of x men, women, and children at the picnic, how many men were there, in terms of x? A. x/2 B. x/3 C. x/4 D. x/5 E. x/6
Official Answer and Stats are available only to registered users. Register/ Login.
Last edited by Bunuel on 24 Apr 2016, 21:31, edited 2 times in total.
Renamed the topic.



VP
Status: Been a long time guys...
Joined: 03 Feb 2011
Posts: 1372
Location: United States (NY)
Concentration: Finance, Marketing
GPA: 3.75

Re: At a picnic there were 3 times as many adults as children [#permalink]
Show Tags
26 Nov 2012, 23:53
2
This post received KUDOS
2
This post was BOOKMARKED
saxenarahul021 wrote: At a picnic there were 3 times as many adults as children and twice as many women as men. If there was a total of x men, women, and children at the picnic, how many men were there, in terms of x?
A. x/2 B. x/3 C. x/4 D. x/5 E. x/6 Hii. I am assuming that the question is "what fraction of men were there?". Answer must be C. Pick a smart number such as: \(Adults>18\) Since the children are three times as many as children, hence \(Children>6\) Further, the adults comprise of Men and women. The given ratio of \(\frac{#women}{#men} = \frac{2}{1}\), therefore \(#women=12, # men=6\). Since the total is Adults+children, i.e. 24. Therefore fraction of men will be \(\frac{6}{24} or \frac{x}{4}\)
_________________
Prepositional Phrases ClarifiedElimination of BEING Absolute Phrases Clarified Rules For Posting www.UnivScholarships.com



Math Expert
Joined: 02 Sep 2009
Posts: 43787

Re: At a picnic there were 3 times as many adults as children [#permalink]
Show Tags
27 Nov 2012, 01:38
3
This post received KUDOS
Expert's post
6
This post was BOOKMARKED



Current Student
Joined: 06 Sep 2013
Posts: 1954
Concentration: Finance

Re: At a picnic there were 3 times as many adults as children [#permalink]
Show Tags
29 May 2014, 05:56
1
This post received KUDOS
1
This post was BOOKMARKED
A=M+W=3C W=2M Then M=C M+W+C=X Then 2M+W=X 4M=X M=X/4 Answer: C Hope this clarifies Cheers! J



Manager
Joined: 05 Dec 2015
Posts: 125

Re: At a picnic there were 3 times as many adults as children [#permalink]
Show Tags
24 Apr 2016, 19:15
Bunuel, I understand your solution, but still am a little confused. The problem says three times as many adults as kids and two times as many women as men, so I had the following:
Adults: 18 Kids: 6
Women: 16 (2/3 * 24 above) Men: 8 (1/3 * 24 above)
so: Men / (Men + Women + Kids) > 8/30
How should I know Men and Women don't include the kids, because they 'boys vs. girls'?
Thanks! I appreciate all you do the forum, you're super helpful.
Michael



Math Expert
Joined: 02 Sep 2009
Posts: 43787

Re: At a picnic there were 3 times as many adults as children [#permalink]
Show Tags
25 Apr 2016, 06:38



Intern
Joined: 06 Apr 2017
Posts: 27

Re: At a picnic there were 3 times as many adults as children [#permalink]
Show Tags
10 Aug 2017, 09:29
1
This post received KUDOS
This question is brutal. I don't know how we should know to assume that the terms "men" and "women" are excluding children. This actually brings me to an important question: what are common verbal traps set in the GMAT quant section similar to this? Is there a reasonable list of indicators that a question may be trying to mislead you verbally?



Manager
Joined: 20 Jan 2016
Posts: 217

Re: At a picnic there were 3 times as many adults as children [#permalink]
Show Tags
13 Oct 2017, 10:28
I am getting x/6. Can someone explain where I am going wrong?
Given: 3A=C and 2W=M (a=adults, C= children, w=women and m=men) x=m+w+c
therefore,
A=w+m 3(w+m)=c 3(m+m/2)=c 9m=2c eq 1
x=m+w+c multiply both side with 2
2x=2m+2w+2c
substitute eq 1
2x=2m+m+9m (2w=m given) 2x=12m m=x/6
help!



Intern
Joined: 04 Sep 2017
Posts: 23
Location: United States
Concentration: Finance
GMAT 1: 610 Q36 V36 GMAT 2: 680 Q40 V36
GPA: 3.3
WE: Consulting (Mutual Funds and Brokerage)

Re: At a picnic there were 3 times as many adults as children [#permalink]
Show Tags
13 Oct 2017, 19:39
2
This post received KUDOS
pra1785 wrote: I am getting x/6. Can someone explain where I am going wrong?
Given: 3A=C and 2W=M (a=adults, C= children, w=women and m=men) x=m+w+c
therefore,
A=w+m 3(w+m)=c 3(m+m/2)=c 9m=2c eq 1
x=m+w+c multiply both side with 2
2x=2m+2w+2c
substitute eq 1
2x=2m+m+9m (2w=m given) 2x=12m m=x/6
help! Hi Pra1987, I believe you are getting mixed up right in the beginning. A=3C and W=2M, not the other way around (Remember the women are 2x are many men and the children are 3x as many adults). When you write 3A=C I think you might be looking at it like 3 adults for every child. That wording is ok, but the math is not. If you are thinking ratios, you need to first say A/C = 3/1 and then solve for one or the other. I solved for A=3/1C or just A=3C. I hope this helps!



Manager
Joined: 20 Jan 2016
Posts: 217

Re: At a picnic there were 3 times as many adults as children [#permalink]
Show Tags
15 Oct 2017, 03:10
zflodeen wrote: pra1785 wrote: I am getting x/6. Can someone explain where I am going wrong?
Given: 3A=C and 2W=M (a=adults, C= children, w=women and m=men) x=m+w+c
therefore,
A=w+m 3(w+m)=c 3(m+m/2)=c 9m=2c eq 1
x=m+w+c multiply both side with 2
2x=2m+2w+2c
substitute eq 1
2x=2m+m+9m (2w=m given) 2x=12m m=x/6
help! Hi Pra1987, I believe you are getting mixed up right in the beginning. A=3C and W=2M, not the other way around (Remember the women are 2x are many men and the children are 3x as many adults). When you write 3A=C I think you might be looking at it like 3 adults for every child. That wording is ok, but the math is not. If you are thinking ratios, you need to first say A/C = 3/1 and then solve for one or the other. I solved for A=3/1C or just A=3C. I hope this helps! You're right. I solved it with a=3c and w=2m and I got the right answer. I think the wording of the question confused me. thank you for the clarification!



Intern
Joined: 04 Sep 2017
Posts: 23
Location: United States
Concentration: Finance
GMAT 1: 610 Q36 V36 GMAT 2: 680 Q40 V36
GPA: 3.3
WE: Consulting (Mutual Funds and Brokerage)

Re: At a picnic there were 3 times as many adults as children [#permalink]
Show Tags
16 Oct 2017, 06:33
Pra1785, I'm happy to help!




Re: At a picnic there were 3 times as many adults as children
[#permalink]
16 Oct 2017, 06:33






