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# At a speed of 50 miles per hour, a certain car uses 1 gallon

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Joined: 16 Apr 2010
Posts: 19
At a speed of 50 miles per hour, a certain car uses 1 gallon  [#permalink]

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Updated on: 09 Feb 2012, 13:18
9
00:00

Difficulty:

25% (medium)

Question Stats:

73% (01:18) correct 27% (01:27) wrong based on 454 sessions

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At a speed of 50 miles per hour, a certain car uses 1 gallon of gasoline every 30 miles. If the car starts with a full 12 gallon tank of gasoline and travels for 5 hours at 50 miles per hour, the amount of gasoline used would be what fraction of a full tank?

A. 3/25
B. 11/36
C. 7/12
D. 2/3
E. 25/36

Originally posted by kilukilam on 27 Jul 2010, 12:31.
Last edited by Bunuel on 09 Feb 2012, 13:18, edited 2 times in total.
Edited the question
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Joined: 02 Sep 2009
Posts: 50711

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27 Jul 2010, 13:28
8
5
At a speed of 50 miles per hour, a certain car uses 1 gallon of gasoline every 30 miles. If the car starts with a full 12 gallon tank of gasoline and travels for 5 hours at 50 miles per hour, the amount of gasoline used would be what fraction of a full tank?

A. 3/25
B. 11/36
C. 7/12
D. 2/3
E. 25/36

In 5 hours at 50 miles per hour car will travel 5*50=250 miles and thus will use 250/30=25/3 gallons of gasoline. Gasoline used/full tank equals to $$\frac{\frac{25}{3}}{12} =\frac{25}{36}$$.

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28 Oct 2011, 15:12
1
My approach:

$$? Gal=5 hours*\frac{50 miles}{1 hour}*\frac{1 Gal}{30 miles}=\frac{25}{3}$$

We write the above equation while we are saying this: How many Gallon we need for 5 hours, while we know that in every 1 hour we go 50 miles, and we know that for every 30 miles we consume 1 Gallon.

and the fraction of used to total:$$\frac{\frac{25}{3}}{12}=\frac{25}{36}$$
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Re: At a speed of 50 miles per hour, a certain car uses 1 gallon  [#permalink]

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21 Aug 2012, 23:23
1
I did the problem differently. Is this a solid approach?

5 hours at 50 MPH, the car will travel 5*50=250 miles

Total capacity of the tank is 12 gallons. At 50 MPH, the car uses 30 miles per gallon.

30*12 = 360 gallons total

$$\frac{250 miles driven}{360 miles tank} = \frac{25}{36}$$
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Posts: 50711
Re: At a speed of 50 miles per hour, a certain car uses 1 gallon  [#permalink]

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22 Aug 2012, 00:13
bmwguy wrote:
I did the problem differently. Is this a solid approach?

5 hours at 50 MPH, the car will travel 5*50=250 miles

Total capacity of the tank is 12 gallons. At 50 MPH, the car uses 30 miles per gallon.

30*12 = 360 gallons total

$$\frac{250 miles driven}{360 miles tank} = \frac{25}{36}$$

The answer is correct but the reasoning is not.

We are told that the car uses 1 gallon of gasoline every 30 miles, so 12 gallons (full tank) of gasoline is enough to travel 12*30=360 miles. Since the car traveled only 250 miles, then it used 250/360=25/36 of full tank.

Hope it's clear.
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Re: At a speed of 50 miles per hour, a certain car uses 1 gallon  [#permalink]

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27 Mar 2015, 06:56
1
5 hours of driving @ 50 miles an hour; 250 total miles
1 liter per 30 miles; 250/30 = 8 1/3
8 1/3 x 3 = 25
12 x 3 = 36

25/36. E.
Intern
Joined: 11 Dec 2012
Posts: 29
At a speed of 50 miles per hour, a certain car uses 1 gallon  [#permalink]

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12 Apr 2015, 03:00
Gazoline used: 50*5 hrs=250
Can be used (full tank): 30*12=360
250/360=25/36
E
Director
Joined: 07 Aug 2011
Posts: 539
GMAT 1: 630 Q49 V27
Re: At a speed of 50 miles per hour, a certain car uses 1 gallon  [#permalink]

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12 Apr 2015, 03:34
kilukilam wrote:
At a speed of 50 miles per hour, a certain car uses 1 gallon of gasoline every 30 miles. If the car starts with a full 12 gallon tank of gasoline and travels for 5 hours at 50 miles per hour, the amount of gasoline used would be what fraction of a full tank?

A. 3/25
B. 11/36
C. 7/12
D. 2/3
E. 25/36

miles driven = 50*5
gasoline consumed= 250/30 = 25/3

gasoline used would be $$\frac{25}{3} * \frac{1}{12}$$ of a full tank .

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Re: At a speed of 50 miles per hour, a certain car uses 1 gallon  [#permalink]

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25 Oct 2016, 16:02
1
1
kilukilam wrote:
At a speed of 50 miles per hour, a certain car uses 1 gallon of gasoline every 30 miles. If the car starts with a full 12 gallon tank of gasoline and travels for 5 hours at 50 miles per hour, the amount of gasoline used would be what fraction of a full tank?

A. 3/25
B. 11/36
C. 7/12
D. 2/3
E. 25/36

We are given that a certain car has a rate of 30 miles per gallon. We are next told that the car starts with a 12-gallon tank and travels for 5 hours at 50 miles per hour.

Since distance = rate x time, we know the car traveled 50 x 5 = 250 miles. We can use the car’s rate and distance traveled to determine how many gallons were used.

Gallons used = distance/rate

Gallons used = 250/30 = 25/3

Finally, we need to determine the amount of gasoline used as a fraction of a full 12-gallon tank.

(25/3)/12 = (25/3) x (1/12) = 25/36

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Intern
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Posts: 2
Re: At a speed of 50 miles per hour, a certain car uses 1 gallon  [#permalink]

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25 Sep 2018, 08:46
I did this one a bit differently and got the right answer in the end...

Just reading the problem we can see that:
1) rate = 50 mi/gal throughout the whole trip
2) car uses 1 gal / 30 min or 2 gal/1 hr

So just reading for about 15 seconds we can see that it would use (5 hr*2 gal/hr)/12 gal = 10/12 gallons.
Which is what I assumed the problem asked when it said "the amount of gasoline used would be what fraction of a full tank?"
Automatically in my head I reduce this to 5/6... but it's not an answer.
However, if I look at choices, I can see that only B, C, E have a denominator where 6 is a factor.
Looking at numerators of those choices, I see that only E has a numerator where 5 is a factor so it must be E because 25/36 reduced is 5/6.

Does this logic make sense?
Re: At a speed of 50 miles per hour, a certain car uses 1 gallon &nbs [#permalink] 25 Sep 2018, 08:46
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