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# Committee X has 4 members, committee Y has 5 members

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Intern
Joined: 03 Feb 2017
Posts: 4
Committee X has 4 members, committee Y has 5 members  [#permalink]

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02 Sep 2018, 12:16
1
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Difficulty:

5% (low)

Question Stats:

90% (00:57) correct 10% (01:29) wrong based on 42 sessions

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Committee X has 4 members, committee Y has 5 members, and these committees have no members in common. If a task force is to be formed consisting of one member of X and one member of Y, how many different task forces are possible?

A) 6
B) 9
C) 10
D) 20
E) 36
GMATH Teacher
Status: GMATH founder
Joined: 12 Oct 2010
Posts: 937
Re: Committee X has 4 members, committee Y has 5 members  [#permalink]

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02 Sep 2018, 13:21
janchang wrote:
Committee X has 4 members, committee Y has 5 members, and these committees have no members in common. If a task force is to be formed consisting of one member of X and one member of Y, how many different task forces are possible?

A) 6
B) 9
C) 10
D) 20
E) 36

Immediate application of the Multiplicative Principle:

If you may choose the member of X among 4 possibilities, and each possibility allows you to choose the member of Y among 5 possibilities, there are 4*5 = 20 possibilities for the task force!

Regards,
fskilnik.
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Fabio Skilnik :: GMATH method creator (Math for the GMAT)
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Posts: 2943
Re: Committee X has 4 members, committee Y has 5 members  [#permalink]

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02 Sep 2018, 13:47

Solution

Given:
• Committee X has 4 members
• Committee Y has 5 members
• A task force is formed consisting of one member of X and one member of Y

To find:
• The number of task force possible.

Approach and Working:

• The number of task force possible= Number of ways to select 1 member from committee X * Number of ways to select 1 member from committee Y
o Hence, total task force possible= 4*5= 20

Hence, the correct answer is option D.

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Re: Committee X has 4 members, committee Y has 5 members   [#permalink] 02 Sep 2018, 13:47
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