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Consider seven integers whose median is 120 and range is 40. The media

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Consider seven integers whose median is 120 and range is 40. The media  [#permalink]

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New post 08 Aug 2019, 08:53
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A
B
C
D
E

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  35% (medium)

Question Stats:

76% (02:06) correct 24% (02:09) wrong based on 25 sessions

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Consider seven integers whose median is \(120\) and range is \(40\). The median for the three smallest integers is \(90\). What is the possible range for the three largest integers?
I. \(35\)
II. \(12\)
III. \(0\)
A) I only
B)II only
C)I and III only
D)II and III only
E)III only
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Re: Consider seven integers whose median is 120 and range is 40. The media  [#permalink]

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New post 08 Aug 2019, 11:58
Imagine this series X,90,...,120,...,...,Y
Y-X=40
The largest possible amount for X is 89. So Y would be 129.
If the smallest number of three numbers is 120, the range would be 129-120=9
Just 0 can be the answer.
Option E

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Re: Consider seven integers whose median is 120 and range is 40. The media  [#permalink]

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New post 08 Aug 2019, 19:29
Let the numbers be
a,90,c,120,e,f,g in ascending order

g - a = 40
if a = 90, g = 130. Now range of largest three can be 130 - 120 = 10, when e =120
Range of largest three cannot be greater than 10.

E is correct.
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Re: Consider seven integers whose median is 120 and range is 40. The media   [#permalink] 08 Aug 2019, 19:29

Consider seven integers whose median is 120 and range is 40. The media

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