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For all numbers x where x ≠ 0, if f(x) is defined by f(x) = 1/x and g(

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Math Expert
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V
Joined: 02 Sep 2009
Posts: 58381
For all numbers x where x ≠ 0, if f(x) is defined by f(x) = 1/x and g(  [#permalink]

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New post 21 Jan 2019, 03:38
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

100% (00:46) correct 0% (00:00) wrong based on 22 sessions

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Joined: 09 Mar 2018
Posts: 996
Location: India
Re: For all numbers x where x ≠ 0, if f(x) is defined by f(x) = 1/x and g(  [#permalink]

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New post 21 Jan 2019, 06:22
Bunuel wrote:
For all numbers x where x ≠ 0, if f(x) is defined by \(f(x) = \frac{1}{x}\) and g(x) is defined by \(g(x) = \frac{1}{(1 + x)}\), then \(f(g(2)) =\)

A 13
B 12
C 1
D 2
E 3


IMO E

g(2) = 1/3

f((g(2))) = 3
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For all numbers x where x ≠ 0, if f(x) is defined by f(x) = 1/x and g(  [#permalink]

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New post 21 Jan 2019, 06:52
\(g(x) =\frac{1}{x+1}\)
\(g(2) =\frac{1}{2+1}\) = \(\frac{1}{3}\)
\(f(g(2))=f(\frac{1}{3})=\frac{1}{\frac{1}{3}}=3\)
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For all numbers x where x ≠ 0, if f(x) is defined by f(x) = 1/x and g(   [#permalink] 21 Jan 2019, 06:52
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For all numbers x where x ≠ 0, if f(x) is defined by f(x) = 1/x and g(

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