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Manager
Joined: 05 Nov 2012
Posts: 163

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16 Nov 2012, 21:36
I saw a formula on this forum but forgot the entire formula and what it is for... can someone pls help me recollect... it looks like x1(y2-y3)+y1(x2-x3)......
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distance.JPG [ 34.87 KiB | Viewed 1206 times ]

Last edited by Amateur on 19 Nov 2012, 10:38, edited 1 time in total.

Kudos [?]: 40 [0], given: 57

Director
Status: Tutor - BrushMyQuant
Joined: 05 Apr 2011
Posts: 618

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Location: India
Concentration: Finance, Marketing
Schools: XLRI (A)
GMAT 1: 700 Q51 V31
GPA: 3
WE: Information Technology (Computer Software)

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16 Nov 2012, 22:37
Hero's Formula
There are several ways to find the area of a triangle. Four of the most useful cases are shown below

a, b, & c are known. This is known as "Heron's Formula".
area = sqrt( S(S-a)(S-b)(S-c) ) where S = 1/2 (a+b+c)
a, b, & C are known
area = 1/2 a b sin(C)
a, B, & C are known
area = a^2/2 sin(B)sin(C)/sin(B+C)
The vertices are known
area = 1/2( x1(y2-y3)+x2(y3-y1)+x3(y1-y2) )

http://www.unitmath.com/um/p/Examples/G ... Plane.html
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Kudos [?]: 794 [0], given: 59

Manager
Joined: 05 Nov 2012
Posts: 163

Kudos [?]: 40 [0], given: 57

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17 Nov 2012, 08:06
thank you for the post.... but none in these gupta..... it has a numerator and a denominator.... for some coordinate geometry problem Bunuel posted a answer with explanation and calculation but some other chap posted a formula in the same page which is a lottttt easier.....

Kudos [?]: 40 [0], given: 57

Manager
Joined: 05 Nov 2012
Posts: 163

Kudos [?]: 40 [0], given: 57

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19 Nov 2012, 10:38
ran in to it once again..... updated my first post with a snapshot of it... Thanks

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