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Re: Given a triangle with sides 5 and 13. [#permalink]

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08 Aug 2009, 10:09

E for me.

1) Since one angle is 90 degrees and two of the sides are 5 and 13 the third side will definitely be 12. This will be one of the legs, i.e. AB or BC. Hence, BC can be 5 or 12. INSUFF.

2) Area is 30. Again we have the same problem. INSUFF Combining also we cannot say for sure which leg is the base and which is the altitude.

Re: Given a triangle with sides 5 and 13. [#permalink]

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08 Aug 2009, 10:14

Is it mentioned in the question that AB & CA are 5 & 13? Or is it given as 5 and 13 are two sides of the triangle. Based on these only we can arrive at the solution. Please post the exact question.

Re: Given a triangle with sides 5 and 13. [#permalink]

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09 Aug 2009, 05:03

1

This post received KUDOS

My answer is C

St 1. We are told that one of the angles is 90 but we don't know which. We know for sure that the side that equals 5 cannot be hypothenuse. Thus, the side 13 can be either the second leg of the right triangle or the hypothenuse. INSF

St2 Gives us an area (30) but we can not derive anything from that

If you combine 2 Stms we are able to identify whether 13 is a leg or hypothenus.

Area=1/2 * H * Base

we know that 5 is a base (or can be a hight) let's try to plug in numbers:

1/2 * 5 * 13 = 32,5 , since we are told that the area=30. Side 13 can not be a leg, thus - hypothenuse. we can say with confidence that the third side = 12 (1/2*5*12=30)