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If 5x5>x1, which of the following must be true?
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04 Jun 2015, 07:14
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If 5x5>x1, which of the following must be true? A. x<1 B. x>1 C. x>5 D. x<5 E. None of the above
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Re: If 5x5>x1, which of the following must be true?
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04 Jun 2015, 07:27




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If 5x5>x1, which of the following must be true?
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04 Jun 2015, 07:31
reto wrote: If 5x5>x1, which of the following must be true?
A. x<1 B. x>1 C. x>5 D. x<5 E. None of the above Best way to solve these question is checking options A. x<1 Take any value of x e.g x=0.5, the primary relation 5x5>x1 is satisfied and but on taking x=2 also the relation holds true which is not considered in option A hence INCORRECTB. x>1 This option can be ruled out straight away as the values of x less than 1 are also acceptable as checked in option A. Hence, INCORRECTC. x>5 This option can be ruled out straight away as the values of x less than 1 are also acceptable as checked in option A. Hence, INCORRECTD. x<5 This option can be ruled out as the values of x Greater than 5 e.g. x=10 are also acceptable and x=1 is not acceptable. Hence, INCORRECTE. None of the above CORRECT
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Re: If 5x5>x1, which of the following must be true?
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09 Jun 2016, 19:49
Bunuel wrote: reto wrote: If 5x5>x1, which of the following must be true?
A. x<1 B. x>1 C. x>5 D. x<5 E. None of the above \(5x5>x1\); Factor out 5: \(5*x1>x1\). Notice here that LHS must more than or equal to 0.If x1 is negative, then (LHS=positive) > (RHS=negative); If x1 is positive, then (LHS=5 times some positive value) > (RHS = that positive positive). If x1 is 0 (so if x=1), then LHS = RHS. Therefore, \(5x5>x1\) holds true for any value of x, but 1. Answer: E. Bunuel, I did it in the following way when x>0 5x5>x1 4x4>0 4(x1)>0 x>1 when x<0 5x+5>x1 6x+6>0 x<1 Now how do i approach the problem? Since I have two different ranges for x, I can say neither must be true??



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Re: If 5x5>x1, which of the following must be true?
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09 Jun 2016, 21:19
reto wrote: If 5x5>x1, which of the following must be true?
A. x<1 B. x>1 C. x>5 D. x<5 E. None of the above This equation can be done by using Mod property. However a simpler way to do it is as follows: 5x5>x1 take 5 common, left hand side becomes 5 * x1 say x1 = y Question then becomes: Is 5y > y? y > always positive. If y is a positive value, then Is 5y > y? > is always true. similarly if y is a negative value, even then Is 5y > y? > is always true. Only when y = 0, does this not hold good. Both A and B can be true, we are not sure. so we cant say that always A will be true or always B will be true. E is the answer.



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Re: If 5x5>x1, which of the following must be true?
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09 Jun 2016, 21:26
mup05ro wrote: Bunuel wrote: reto wrote: If 5x5>x1, which of the following must be true?
A. x<1 B. x>1 C. x>5 D. x<5 E. None of the above \(5x5>x1\); Factor out 5: \(5*x1>x1\). Notice here that LHS must more than or equal to 0.If x1 is negative, then (LHS=positive) > (RHS=negative); If x1 is positive, then (LHS=5 times some positive value) > (RHS = that positive positive). If x1 is 0 (so if x=1), then LHS = RHS. Therefore, \(5x5>x1\) holds true for any value of x, but 1. Answer: E. Bunuel, I did it in the following way when x>0 5x5>x1 4x4>0 4(x1)>0 x>1 when x<0 5x+5>x1 6x+6>0 x<1 Now how do i approach the problem? Since I have two different ranges for x, I can say neither must be true?? x > 0 and x < 0 have no role to play in this question. The ranges you must consider are (x  1) >= 0 and (x  1) < 0. I have explained why here: http://www.veritasprep.com/blog/2014/06 ... thegmat/
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Re: If 5x5>x1, which of the following must be true?
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10 Jun 2016, 03:23
VeritasPrepKarishma wrote: mup05ro wrote: reto wrote: If 5x5>x1, which of the following must be true?
A. x<1 B. x>1 C. x>5 D. x<5 E. None of the above Bunuel, I did it in the following way when x>0 5x5>x1 4x4>0 4(x1)>0 x>1 when x<0 5x+5>x1 6x+6>0 x<1 Now how do i approach the problem? Since I have two different ranges for x, I can say neither must be true?? x > 0 and x < 0 have no role to play in this question. The ranges you must consider are (x  1) >= 0 and (x  1) < 0. thank you karishma now that from (x  1) >= 0 and (x  1) < 0 we know x>=1 and x<1 , what do we understand? should I think that since x cannot be both greater than and less than 1, neither is correct?



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If 5x5>x1, which of the following must be true?
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Updated on: 07 Nov 2017, 08:11
mup05ro wrote: Bunuel wrote: reto wrote: If 5x5>x1, which of the following must be true?
A. x<1 B. x>1 C. x>5 D. x<5 E. None of the above \(5x5>x1\); Factor out 5: \(5*x1>x1\). Notice here that LHS must more than or equal to 0.If x1 is negative, then (LHS=positive) > (RHS=negative); If x1 is positive, then (LHS=5 times some positive value) > (RHS = that positive positive). If x1 is 0 (so if x=1), then LHS = RHS. Therefore, \(5x5>x1\) holds true for any value of x, but 1. Answer: E. Bunuel, I did it in the following way when x>0 5x5>x1 4x4>0 4(x1)>0 x>1 when x<0 5x+5>x1 6x+6>0 x<1 Now how do i approach the problem? Since I have two different ranges for x, I can say neither must be true??



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Re: If 5x5>x1, which of the following must be true?
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04 Nov 2017, 11:10
reto wrote: If 5x5>x1, which of the following must be true?
A. x<1 B. x>1 C. x>5 D. x<5 E. None of the above I think the main nuance here is "which of the following must be true". Not "can, could". It is pretty obvious but since nobody mentioned it... Maybe this is the reson why many people choose B or even A.




Re: If 5x5>x1, which of the following must be true? &nbs
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04 Nov 2017, 11:10






