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Re: If a and b are twodigit positive integers greater than 10
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17 Dec 2018, 18:37
Bunuel wrote: SOLUTIONIf \(a\) and \(b\) are twodigit positive integers greater than 10, is the remainder when \(a\) is divided by 11 less than the remainder when \(b\) is divided by 11?First of all, note that the remainder when a positive integer is divided by 11 could be 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 or 10. (1) The remainder when \(a\) is divided by 69 is the fifth power of a prime number: \(a=69q+prime^5\) and \(prime^5<69\) (the remainder must be less than the divisor). The only prime number whose fifth power is less than 69 is 2: \((2^5=32) < 69\). So, we have that \(a=69q+32\): 32, 101, 170, ... Since \(a\) is a twodigit integer, then \(a=32\). Now, \(a=32\) divided by 11 gives the remainder of 10. Since 10 is the maximum remainder possible when divided by 11, then this remainder cannot be less then the remainder when \(b\) is divided by 11 (0, 1, 2, 3, 4, 5, 6, 7, 8, 9 or 10). So, the answer to the question is NO. Sufficient. (2) The remainder when \(b\) is divided by 12 is \(b\): The remainder must be less than the divisor, hence \(b\) must be less than 12 and since we are told that \(b\) is a twodigit integers greater than 10, then \(b\) must be 11. Now, \(b=11\) divided by 11 gives the remainder of 0. Since 0 is the minimum remainder possible, than the remainder when \(a\) is divided by 11 cannot possible be less than 0. So, the answer to the question is NO. Sufficient. Answer: D. Try NEW remainders PS question. Hi Bunuel, I don't think option 2 is alone sufficient as they have not provided in question that a and b are two different integers, As per option 2 I agree that b must be 11 but what a is also valued as 11. Correct me if I am missing something. gmatbusters Could you please also review above mention doubt of mine and advise.
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Re: If a and b are twodigit positive integers greater than 10
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17 Dec 2018, 19:01
Hi Gmatprep550As per statement 2, b is 11. Hence the remainder when b is divided by 11 is 0. Now 0 is the minimum remainder possible, a cannot give remainder lower than 0. Your doubt: even if both a and b are equal. Both remainders would be same = 0. We can definitely say remainder when a is divided by 11 can not be lower than remainder when b is divided by 11 Hope, it is clear now. Don't hesitate to tag me again . Gmatprep550 wrote: Bunuel wrote: SOLUTIONIf \(a\) and \(b\) are twodigit positive integers greater than 10, is the remainder when \(a\) is divided by 11 less than the remainder when \(b\) is divided by 11?First of all, note that the remainder when a positive integer is divided by 11 could be 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 or 10. (1) The remainder when \(a\) is divided by 69 is the fifth power of a prime number: \(a=69q+prime^5\) and \(prime^5<69\) (the remainder must be less than the divisor). The only prime number whose fifth power is less than 69 is 2: \((2^5=32) < 69\). So, we have that \(a=69q+32\): 32, 101, 170, ... Since \(a\) is a twodigit integer, then \(a=32\). Now, \(a=32\) divided by 11 gives the remainder of 10. Since 10 is the maximum remainder possible when divided by 11, then this remainder cannot be less then the remainder when \(b\) is divided by 11 (0, 1, 2, 3, 4, 5, 6, 7, 8, 9 or 10). So, the answer to the question is NO. Sufficient. (2) The remainder when \(b\) is divided by 12 is \(b\): The remainder must be less than the divisor, hence \(b\) must be less than 12 and since we are told that \(b\) is a twodigit integers greater than 10, then \(b\) must be 11. Now, \(b=11\) divided by 11 gives the remainder of 0. Since 0 is the minimum remainder possible, than the remainder when \(a\) is divided by 11 cannot possible be less than 0. So, the answer to the question is NO. Sufficient. Answer: D. Try NEW remainders PS question. Hi Bunuel, I don't think option 2 is alone sufficient as they have not provided in question that a and b are two different integers, As per option 2 I agree that b must be 11 but what a is also valued as 11. Correct me if I am missing something. gmatbusters Could you please also review above mention doubt of mine and advise. Posted from my mobile device
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If a and b are twodigit positive integers greater than 10
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18 Dec 2018, 07:11
Hi gmatbusters, Thanks for quick response, I guess I got your point and wanted to make sure what I understood is correct. As per your below mentioned statement what I am getting is remainder when a is divided by 11 can not be lower than remainder when b is divided by 11 as it's going to be equal or more."We can definitely say remainder when a is divided by 11 can not be lower than remainder when b is divided by 11"
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Location: India
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WE: Business Development (Energy and Utilities)

Re: If a and b are twodigit positive integers greater than 10
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18 Dec 2018, 07:13
You got it Right. Gmatprep550 wrote: Hi gmatbusters, Thanks for quick response, I guess I got your point and wanted to make sure what I understood is correct. As per your below mentioned statement what I am getting is remainder when a is divided by 11 can not be lower than remainder when b is divided by 11 as it's going to be equal or more."We can definitely say remainder when a is divided by 11 can not be lower than remainder when b is divided by 11"
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Re: If a and b are twodigit positive integers greater than 10
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18 Dec 2018, 07:19
Thanks again for quick response, you rock !! gmatbusters wrote: You got it Right. Gmatprep550 wrote: Hi gmatbusters, Thanks for quick response, I guess I got your point and wanted to make sure what I understood is correct. As per your below mentioned statement what I am getting is remainder when a is divided by 11 can not be lower than remainder when b is divided by 11 as it's going to be equal or more."We can definitely say remainder when a is divided by 11 can not be lower than remainder when b is divided by 11"
_________________
______________________________ Consider KUDOS if my post helped !!
I'd appreciate learning about the grammatical errors in my posts
Please let me know if I'm wrong somewhere




Re: If a and b are twodigit positive integers greater than 10 &nbs
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18 Dec 2018, 07:19



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