GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 20 Oct 2019, 19:41 GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.  Consider two integers: an original two digits integer and the integer

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
Manager  B
Joined: 15 Dec 2015
Posts: 50
Consider two integers: an original two digits integer and the integer  [#permalink]

Show Tags 00:00

Difficulty:   75% (hard)

Question Stats: 50% (01:23) correct 50% (01:28) wrong based on 22 sessions

HideShow timer Statistics

Consider two integers: an original two digits integer and the integer formed by reversing the digits of this original integer. If the bigger of these two integers is divided by the other integer, what could be the maximum remainder?
1) 9
2)27
3)36
4)45
5) 54

Originally posted by Nina1987 on 17 Apr 2018, 05:49.
Last edited by Nina1987 on 17 Apr 2018, 14:38, edited 1 time in total.
Senior Manager  G
Joined: 14 Feb 2018
Posts: 387
Re: Consider two integers: an original two digits integer and the integer  [#permalink]

Show Tags

32/23 gives remainder 9.

42/24 gives remainder 18.

94/49 gives remainder 45.

98/89 gives remainder 9.

Likewise, by putting certain values, answer can be determined. Thus, maximum is 45.

Hence option D.

Posted from my mobile device
Manager  B
Joined: 15 Dec 2015
Posts: 50
Re: Consider two integers: an original two digits integer and the integer  [#permalink]

Show Tags

1
SonalSinha803 wrote:
32/23 gives remainder 9.

42/24 gives remainder 18.

94/49 gives remainder 45.

98/89 gives remainder 9.

Likewise, by putting certain values, answer can be determined. Thus, maximum is 45.

Hence option D.

Posted from my mobile device

HOw did you choose those numbers? Randomly or is there any method?
Intern  B
Joined: 14 Feb 2018
Posts: 17
Re: Consider two integers: an original two digits integer and the integer  [#permalink]

Show Tags

Nina1987 wrote:
SonalSinha803 wrote:
32/23 gives remainder 9.

42/24 gives remainder 18.

94/49 gives remainder 45.

98/89 gives remainder 9.

Likewise, by putting certain values, answer can be determined. Thus, maximum is 45.

Hence option D.

Posted from my mobile device

HOw did you choose those numbers? Randomly or is there any method?

I am also confused as to how you chose those numbers to test with.
Senior Manager  G
Joined: 29 Dec 2017
Posts: 378
Location: United States
Concentration: Marketing, Technology
GMAT 1: 630 Q44 V33 GMAT 2: 690 Q47 V37 GMAT 3: 710 Q50 V37 GPA: 3.25
WE: Marketing (Telecommunications)
Re: Consider two integers: an original two digits integer and the integer  [#permalink]

Show Tags

Nina1987 wrote:
If a two digit integer is divided by an integer formed by reversing its digits, what could be the maximum remainder?

A. 9
B. 27
C. 36
D. 45
E. 54

How about 89 and 98 when 89 in nominator and 98 in denominator? 89>45

I think that the question is incorrect.
Manager  B
Joined: 15 Dec 2015
Posts: 50
Re: Consider two integers: an original two digits integer and the integer  [#permalink]

Show Tags

Hero8888 wrote:
Nina1987 wrote:
If a two digit integer is divided by an integer formed by reversing its digits, what could be the maximum remainder?

A. 9
B. 27
C. 36
D. 45
E. 54

How about 89 and 98 when 89 in nominator and 98 in denominator? 89>45

I think that the question is incorrect.

sorry just edited the question. pls check now.
Manager  G
Joined: 30 Mar 2017
Posts: 125
GMAT 1: 200 Q1 V1 Re: Consider two integers: an original two digits integer and the integer  [#permalink]

Show Tags

1
Since this is a max problem, one strategy is to see if the max answer choice (Option E) fits. If it does, you've found the answer. If not, try Option D.

To maximize the remainder, we need to maximize the smaller 2-digit integer. The smaller 2-digit integer is the divisor, and the remainder is less than the divisor. So if the divisor is 12, most we can hope for is a remainder of 11. On the other hand, if the divisor is 60, we can have a remainder as high as 59. But note that the max remainder we can have when a larger 2-digit integer is divided by a smaller 2-digit integer is 49 (99/50). This eliminates Option E.

Let's see if Option D can work. I'll leave it to you to see why having a denominator greater than 50 wont give you a remainder of 45. Let's go the other way and try the next denominator down, 49 --> 94/49 yields a remainder of 45, which is Option D. Re: Consider two integers: an original two digits integer and the integer   [#permalink] 17 Apr 2018, 20:28
Display posts from previous: Sort by

Consider two integers: an original two digits integer and the integer

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne  