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Re: If n denotes a number to the left of 0 on the number line [#permalink]

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10 Jul 2017, 19:39

Math mods and others - Please check my approach:

Given: n is less than 0, implying n is negative.

Also given: \(n^2\) < \(\frac{1}{100}\)

Square rooting both sides:

n< -\(\frac{1}{10}\) AND n < \(\frac{1}{10}\)

Reciprocating both the inequalities, \(\frac{1}{n}\) <-10 AND \(\frac{1}{n}\) <10

Since, \(\frac{1}{n}\) MUST be less than -10 and 10 at all times, the option that always satisfies this is A.

Is this a right approach? I always falter when removing the squares on both sides of the equation/inequality and I want to make sure my approach is correct so that I can register it in my noggin.

Re: If n denotes a number to the left of 0 on the number line [#permalink]

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26 Aug 2017, 08:41

experts, please correct me if i'm wrong:

isn't it easy to just take a glance here and eliminate A/C? - You're told the SQUARE of n = fraction meaning n = fraction --> The reciprocal of n must therefore b an integer. Elim B, C, D straight away

Between A & E, you know that n = negative, so its reciprocal cannot be positive. Elim E.