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Re: If n is a positive integer, what is the remainder when (7^n + 5) is di [#permalink]
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If n is a positive integer, what is the remainder when (7^n + 5) is divided by 10?

(1) When n is divided by 4, the remainder is 1.

\(n=4x+1\)
\(7^(4x+1) + 5\)
unit digit of this number will be \(7+5=12 \)
we get the remainder \(2\) when divided by \(10\)

(2) When n is divided by 12, the remainder is 5.

\(n=12x+5\)
\(7^(12x+5) + 5\)
unit digit of this number will be \(7+5=12 \)
we get the remainder \(2\) when divided by \(10\)

So D
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Re: If n is a positive integer, what is the remainder when (7^n + 5) is di [#permalink]
yashikaaggarwal wrote:
To find: If n is a positive integer, what is the remainder when (7^n + 5) is divided by 10?

(1) When n is divided by 4, the remainder is 1.
N = 1,5,9,13,17............
(unit digit of 7)
7^1 = 7
7^2 = 9
7^3 = 3
7^4 = 1
7^5 = 7
7^6 = 9
......
Cyclicity of 7 repeats after 4
So 7^1,5,9.... Will give 7 as unit digit. So 7^n+5 = 7+5 = 12. Remainder will be 2 when divided by 10
(Sufficient)

(2) When n is divided by 12, the remainder is 5.
N = 5,17,29,41............
(unit digit of 7)
7^1 = 7
7^2 = 9
7^3 = 3
7^4 = 1
7^5 = 7
7^6 = 9
......
Cyclicity of 7 repeats after 4
So 7^5,17.... Will give 7 as unit digit. So 7^n+5 = 7+5 = 12. Remainder will be 2 when divided by 10
(Sufficient)

Answer is D

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yashikaaggarwal what is the relation between unit digit cyclicty and finding of remainder ? :? one thing to know the last digit of number and another thing to know a whole number ... yes cyclycty repeats after 4, so what ?

dammit still have questions with quant :lol:
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Re: If n is a positive integer, what is the remainder when (7^n + 5) is di [#permalink]
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dave13 wrote:
yashikaaggarwal wrote:
To find: If n is a positive integer, what is the remainder when (7^n + 5) is divided by 10?

(1) When n is divided by 4, the remainder is 1.
N = 1,5,9,13,17............
(unit digit of 7)
7^1 = 7
7^2 = 9
7^3 = 3
7^4 = 1
7^5 = 7
7^6 = 9
......
Cyclicity of 7 repeats after 4
So 7^1,5,9.... Will give 7 as unit digit. So 7^n+5 = 7+5 = 12. Remainder will be 2 when divided by 10
(Sufficient)

(2) When n is divided by 12, the remainder is 5.
N = 5,17,29,41............
(unit digit of 7)
7^1 = 7
7^2 = 9
7^3 = 3
7^4 = 1
7^5 = 7
7^6 = 9
......
Cyclicity of 7 repeats after 4
So 7^5,17.... Will give 7 as unit digit. So 7^n+5 = 7+5 = 12. Remainder will be 2 when divided by 10
(Sufficient)

Answer is D

Posted from my mobile device



yashikaaggarwal what is the relation between unit digit cyclicty and finding of remainder ? :? one thing to know the last digit of number and another thing to know a whole number ... yes cyclycty repeats after 4, so what ?

dammit still have questions with quant :lol:

Okay so if we start from start.
we know any no. ending with 1to9 leaves same remainder as its unit digit.
For ex- 11/10 leaves remainder 1. 29/10 leaves remainder 9 and so on.
so we just have to find what's the unit digit of 7^n+5, cool.

now 1st statement says when n is divided by 4 it leaves remainder 1.
then value of n = 1,5,9,13,17............
as stated above 7 unit digit repeats after every 4th power.
and 7^1 unit digit = 7^5 unit digit = 7^9 unit digit (the powers are at the gap of 4)
so the unit digit of every power of 7^5 in this statement is 7
and adding 5 in 7 will give you 12 or simply 2 as unit digit, which will be same when we divide the no. ending with 2 as unit digit with 10.
hence its sufficient.

Similarly for other statement.
Hopefully this helps.
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Re: If n is a positive integer, what is the remainder when (7^n + 5) is di [#permalink]
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Re: If n is a positive integer, what is the remainder when (7^n + 5) is di [#permalink]
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