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If P and Q represent the hundreds and tens digits, respectively, in th [#permalink]
Expert Reply
Is 8PQ2 divisible by 8?
Divisibility rule of 8:
If the last three digits of a number are divisible by 8, then the number is completely divisible by 8.
Last 3 digits in 8PQ2 are PQ2.
We will check last three digits only.


Statement 1:
P = 4
=>PQ2 = 4Q2.
If Q = {3, 7}, then PQ2 is divisible by 8.
For all other values of Q, PQ2 is not divisible by 8
Statement 1 is Not Sufficient.

Statement 2:
Q = 0
=>PQ2 = P02
For any value of P, PQ2 is not divisible by 8
Statement 2 is Sufficient.

So, correct answer is option B.

Originally posted by MarmikUpadhyay on 15 Mar 2021, 01:08.
Last edited by MarmikUpadhyay on 15 Mar 2021, 01:48, edited 2 times in total.
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Re: If P and Q represent the hundreds and tens digits, respectively, in th [#permalink]
Expert Reply
MarmikUpadhyay wrote:
Is 8PQ2 divisible by 8?
Divisibility rule of 8:
If the last three digits of a number are divisible by 8, then the number is completely divisible by 8.
Last 3 digits in 8PQ2 are PQ2.
We will check last three digits only.


Statement 1:
P = 4
=>PQ2 = 4Q2.
If Q = {3, 7}, then PQ2 is divisible by 8.
For all other values of Q, PQ2 is not divisible by 8
Statement 1 is Not Sufficient.

Statement 2:
Q = 0
=>PQ2 = P02
If P = {1, 3, 5, 7, 9}, then PQ2 is divisible by 8.
For even values of P, PQ2 is not divisible by 8
Statement 2 is also Not Sufficient.

Statement 1 and Statement 2 combined:
P = 4 and Q = 0
=> PQ2 = 402
402 is not divisible by 8. Therefore, 8402 is also not divisible by 8.
Statement 1 and Statement 2 together are Sufficient.

So, correct answer is option C.



You will have to look into your solution.

102, 202, 302 and so on are not divisible by 4, leave aside 8.
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Re: If P and Q represent the hundreds and tens digits, respectively, in th [#permalink]
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If P and Q represent the hundreds and tens digits, respectively, in the four-digit number x=8PQ2, is x divisible by 8?

Stat1: P=4
then, x =84Q2, it can be divisible by 8 or not. Not sufficient.

Stat2: Q=0
then, x =8P02, we can have any digit for P, but x won't be divisible by 8.

x =8P02, if last two digits is 02, x won't be divisible by 8.
x =8P02, if last two digits is 22, x won't be divisible by 8.
x =8P02, if last two digits is 42, x won't be divisible by 8.
x =8P02, if last two digits is 62, x won't be divisible by 8.
x =8P02, if last two digits is 82, x won't be divisible by 8.
Sufficient.

So, I think B. :)
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Re: If P and Q represent the hundreds and tens digits, respectively, in th [#permalink]
1
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If P and Q represent the hundreds and tens digits, respectively, in the four-digit number x=8PQ2, is x divisible by 8?

(1) P=4

x = 84Q2
For Q=2, 8422 is not divisible
For Q=3, 8432 is divisible
Not sufficient

(2) Q=0

x = 8P02
The last two digits are not divisible by 4. So, 8P02 is not divisible by 8.
Sufficient

Option B

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Re: If P and Q represent the hundreds and tens digits, respectively, in th [#permalink]
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Re: If P and Q represent the hundreds and tens digits, respectively, in th [#permalink]
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