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20 Feb 2014, 01:19
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C
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Difficulty:
15%
(low)
Question Stats:
80% (01:25) correct
20%
(01:14)
wrong
based on 1896
sessions
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If \(t\neq{0}\), is r greater than zero?
(1) rt = 12
(2) r + t = 7
(1) rt = 12
(2) r + t = 7
20 Feb 2014, 01:20
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SOLUTION
If \(t\neq{0}\), is r greater than zero?
(1) rt = 12 --> if r=1 and t=12, then r>0 but if r=-1 and t=-12, then r<0. Not sufficient.
(2) r + t = 7 --> if r=1 and t=6, then r>0 but if r=-1 and t=8, then r<0. Not sufficient.
(1)+(2) From (2) t = 7- r, thus from (1) r(7-r) = 12 --> solving gives r=3 or r=4. In ether case r>0. Sufficient.
Answer: C.
If \(t\neq{0}\), is r greater than zero?
(1) rt = 12 --> if r=1 and t=12, then r>0 but if r=-1 and t=-12, then r<0. Not sufficient.
(2) r + t = 7 --> if r=1 and t=6, then r>0 but if r=-1 and t=8, then r<0. Not sufficient.
(1)+(2) From (2) t = 7- r, thus from (1) r(7-r) = 12 --> solving gives r=3 or r=4. In ether case r>0. Sufficient.
Answer: C.
General Discussion
20 Feb 2014, 04:08
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If \(t\neq{0}\), is r greater than zero?
(1) rt = 12
(2) r + t = 7
1 - insufficient. If t<0 -> r<0, if t>0 -> r>0.
2 - insufficient. Could be r=-1 and t=8, or r=1 and t=6.
2 and 2:
\(r+\frac{12}{t}-7=0\)
\(r^2 -7r+12=0\)
\((r-1)(r-6)=0\)
So r=1 or 6. That are >0.
Ans C
(1) rt = 12
(2) r + t = 7
1 - insufficient. If t<0 -> r<0, if t>0 -> r>0.
2 - insufficient. Could be r=-1 and t=8, or r=1 and t=6.
2 and 2:
\(r+\frac{12}{t}-7=0\)
\(r^2 -7r+12=0\)
\((r-1)(r-6)=0\)
So r=1 or 6. That are >0.
Ans C
