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If t ≠ 0, is r greater than zero?
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20 Feb 2014, 01:19
20 Feb 2014, 01:19
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A
B
C
D
E
Difficulty:
15%
(low)
Question Stats:
79% (01:25) correct
21%
(01:18)
wrong
based on 1713
sessions
Re: If t ≠ 0, is r greater than zero?
[#permalink]
20 Feb 2014, 01:20
20 Feb 2014, 01:20
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Expert Reply
SOLUTION
If \(t\neq{0}\), is r greater than zero?
(1) rt = 12 --> if r=1 and t=12, then r>0 but if r=-1 and t=-12, then r<0. Not sufficient.
(2) r + t = 7 --> if r=1 and t=6, then r>0 but if r=-1 and t=8, then r<0. Not sufficient.
(1)+(2) From (2) t = 7- r, thus from (1) r(7-r) = 12 --> solving gives r=3 or r=4. In ether case r>0. Sufficient.
Answer: C.
If \(t\neq{0}\), is r greater than zero?
(1) rt = 12 --> if r=1 and t=12, then r>0 but if r=-1 and t=-12, then r<0. Not sufficient.
(2) r + t = 7 --> if r=1 and t=6, then r>0 but if r=-1 and t=8, then r<0. Not sufficient.
(1)+(2) From (2) t = 7- r, thus from (1) r(7-r) = 12 --> solving gives r=3 or r=4. In ether case r>0. Sufficient.
Answer: C.
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Re: If t ≠ 0, is r greater than zero?
[#permalink]
02 Jun 2014, 18:05
02 Jun 2014, 18:05
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No calculations approach:
If t#0, is r greater than zero?
(1) rt = 12
(2) r + t = 7
St1: Both r and t could be positive or both r and t could be negative. Not Suff
St2: Both r and t could be positive or either of r and t could be negative. Not Suff
1+2 --> common possibility is both r and t are positive. So r is positive i.e. greater than 0.
Ans:C
If t#0, is r greater than zero?
(1) rt = 12
(2) r + t = 7
St1: Both r and t could be positive or both r and t could be negative. Not Suff
St2: Both r and t could be positive or either of r and t could be negative. Not Suff
1+2 --> common possibility is both r and t are positive. So r is positive i.e. greater than 0.
Ans:C
