Hi All,

We're told that the sum of 7 POSITIVE INTEGERS is LESS than 12. Since that sum has to be so small, there are a limited number of possibilities for the 7 integers. For example....

We could have....

Seven 1s - and the sum would be 7

Five 1s and two 2s - and the sum would be 9

Six 1s and one 4 - and the sum would be 10

Four 1s, two 2s and one 3 - and the sum would be 11

Etc.

We're asked for the RANGE of the 7 integers.

1) The sum of the 7 integers is 11

With a sum of 11, we could have....

Four 1s, two 2s and one 3 - and the RANGE = 2

Six 1s and one 5 - and the RANGE = 4

Fact 1 is INSUFFICIENT

2) The median of the 7 integers is 2

With a MEDIAN of 2, we must have three numbers less than/equal to 2 and three other numbers greater than/equal to 2...

_ _ _ 2 _ _ _

Since we're dealing with POSITIVE INTEGERS, there's only one way for this to occur...

1 1 1 2 2 2 2

Thus, the range MUST equal 1.

Fact 2 is SUFFICIENT

Final Answer:

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Rich

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