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# If there are 32 guests at a party, what is the average (arithmetic mea

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Math Expert
Joined: 02 Sep 2009
Posts: 64163
If there are 32 guests at a party, what is the average (arithmetic mea  [#permalink]

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04 May 2020, 03:00
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Difficulty:

25% (medium)

Question Stats:

81% (00:35) correct 19% (00:52) wrong based on 27 sessions

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If there are 32 guests at a party, what is the average (arithmetic mean) age of the guests?

(1) The sum of the ages of the guests is 1536 years

(2) The youngest guest, Tracy, is 24 years old and the oldest guest, Pat, is 68 years old

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If there are 32 guests at a party, what is the average (arithmetic mea  [#permalink]

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04 May 2020, 03:57
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Bunuel wrote:
If there are 32 guests at a party, what is the average (arithmetic mean) age of the guests?

(1) The sum of the ages of the guests is 1536 years

(2) The youngest guest, Tracy, is 24 years old and the oldest guest, Pat, is 68 years old

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Question: Average Age of Guests $$= \frac{Total-Guest-Age}{Total-Guests} = \frac{Total-Guest-Age}{32}$$

Given: Total Guests = 32

Statement 1: The sum of the ages of the guests is 1536 years

SUFFICIENT

Statement 2: The youngest guest, Tracy, is 24 years old and the oldest guest, Pat, is 68 years old

Total age of all guests is unknown hence

NOT SUFFICIENT

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If there are 32 guests at a party, what is the average (arithmetic mea  [#permalink]

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04 May 2020, 10:17
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Average age of guests = (Sum of age of all guests / Number of guests)

Since, this is a "WHAT" question, we need a definite answer

Statement 1: Sum of all guests is 1536 and we know total number of guests are 32

1536/32 = 48 (Sufficient)

Statement 2: Age of youngest and oldest guest is given but no information regarding other guest's ages

(Insufficient)

If there are 32 guests at a party, what is the average (arithmetic mea   [#permalink] 04 May 2020, 10:17