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Re: If x = 0.888, y = 0.888^(1/2), and z = (0.888)^2, then which of the fo [#permalink]
another way of doing it is to square every number:

so x^2=(0.888)^2
y^2= 0.888
z^2=(0.888)^4
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Re: If x = 0.888, y = 0.888^(1/2), and z = (0.888)^2, then which of the fo [#permalink]
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Bunuel wrote:
If \(x = 0.888\), \(y = \sqrt{0.888}\), and \(z = (0.888)^2\), then which of the following is true?


(A) x < y < z

(B) x < z < y

(C) y < x < z

(D) y < z < x

(E) z < x < y


Since squaring a decimal value that is between 0 and 1 makes it smaller and since taking the square root of such a decimal makes it larger, we have:

z < x < y

Answer: E
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If x = 0.888, y = 0.888^(1/2), and z = (0.888)^2, then which of the fo [#permalink]
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Bunuel wrote:
If \(x = 0.888\), \(y = \sqrt{0.888}\), and \(z = (0.888)^2\), then which of the following is true?


(A) x < y < z

(B) x < z < y

(C) y < x < z

(D) y < z < x

(E) z < x < y

Under pressure, a test taker can get confused easily about number properties. Testing a number is a smart way to be sure.

We do not have to assess 0.888 (\(=\frac{888}{1,000}\))

Proper fractions (between 0 and 1) and their decimal equivalents all behave the same way.

Make life easy. Choose a different fraction, one that has an easy square root
Let
\(x=\frac{1}{4}\)
\(y =\sqrt{\frac{1}{4}}=\frac{1}{2}\)
\(z=(\frac{1}{4})^2=\frac{1}{16}\)


\(z\) is the smallest. Only one answer is available (and \(z<x<y\))

Answer E
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Re: If x = 0.888, y = 0.888^(1/2), and z = (0.888)^2, then which of the fo [#permalink]
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Re: If x = 0.888, y = 0.888^(1/2), and z = (0.888)^2, then which of the fo [#permalink]
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