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# If (x - 2)(x + 2)(x - 3)(x + 5)(x + 9) = 0, what is the ratio of the

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Joined: 02 Sep 2009
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If (x - 2)(x + 2)(x - 3)(x + 5)(x + 9) = 0, what is the ratio of the  [#permalink]

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07 Mar 2019, 02:47
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25% (medium)

Question Stats:

82% (00:48) correct 18% (00:22) wrong based on 11 sessions

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If $$(x - 2)(x + 2)(x - 3)(x + 5)(x + 9) = 0$$, what is the ratio of the greatest possible value of x to the least possible value of x?

A. -1/3

B. -2/9

C. 3/2

D. 3

E. 9/2

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Posts: 1468
Concentration: Accounting, Finance
GPA: 3.68
WE: Analyst (Accounting)
If (x - 2)(x + 2)(x - 3)(x + 5)(x + 9) = 0, what is the ratio of the  [#permalink]

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07 Mar 2019, 02:55
Bunuel wrote:
If $$(x - 2)(x + 2)(x - 3)(x + 5)(x + 9) = 0$$, what is the ratio of the greatest possible value of x to the least possible value of x?

A. -1/3

B. -2/9

C. 3/2

D. 3

E. 9/2

NOTE: Ultimate result is 0. Thus , for each equal positive or negative value of x , this equation holds true. Another thing is that there is multiplication relationship among all the items.

Given,

$$(x - 2)(x + 2)(x - 3)(x + 5)(x + 9) = 0$$

we will try to take one positive and one positive value.

x + 9 = 0

x = -9.............This is least

one positive value.

x - 3 = 0

x = 3.

Required Ratio : 3/-9 = - 1/3.

If (x - 2)(x + 2)(x - 3)(x + 5)(x + 9) = 0, what is the ratio of the   [#permalink] 07 Mar 2019, 02:55
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