heyholetsgo wrote:

If x^2y^3=200, what is xy?

1.) y is an integer

2.) x/y= 2.5

why is it not e? Don't we get 2 solutions for x once we get the value for y?

Even though, the solution has already been provided above, I want to point out something. The silver lining of DS questions is that you don't need to solve. If you know you will get a unique value, you are done.

Question stem: If \(x^2y^3=200\), what is xy?

Statement 1: y is an integer but x needn't be.

If y = 1, \(x = +-\sqrt{200}\)

If y = 2, x = +-5 etc

We do not know what xy is.

Statement 2:\(\frac{x}{y} = \frac{5}{2}\)

This means \(x = (\frac{5}{2})y\)

This value of x you can put above to get a unique value of y. (Since you will get y^5 = ... An odd power will give you only the positive solution here. )

Once you have the value of y, you get a unique value for x and hence you get a value for xy.

_________________

Karishma

Veritas Prep GMAT Instructor

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