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# If x and y are integers, what is the value of (x-y)^2?

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Manager
Joined: 15 Dec 2015
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If x and y are integers, what is the value of (x-y)^2?  [#permalink]

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31 Jul 2017, 00:33
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54% (01:09) correct 46% (01:25) wrong based on 67 sessions

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If x and y are integers, what is the value of (x-y)^2?

Statement1: The product of x and y is -5.
Statement2: x>y
Senior Manager
Joined: 24 Jun 2012
Posts: 378
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Concentration: Strategy, International Business
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Re: If x and y are integers, what is the value of (x-y)^2?  [#permalink]

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31 Jul 2017, 00:44
Is it C? Statment one tells that two values are 1 and - 5 or -1 or 5 and statement 2 tells which one if greater. Taking any value of x as 1 or 5 we get one asnwer for x-y and that is 6

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Re: If x and y are integers, what is the value of (x-y)^2?  [#permalink]

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31 Jul 2017, 00:50
1
Oh i got it, its square of x-y so any negative value will get positive..so either x is -ve or positive we get the same answer...good question

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Re: If x and y are integers, what is the value of (x-y)^2?  [#permalink]

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31 Jul 2017, 09:51
2
I guess it's A

We can change the needed value a little bit

X^2 + Y^2 - 2XY

From the first statement we can infer that the pairs of X and Y can be either (1,-5) or (-1,5).

Putting either of these pairs in the above value will give

1^2 + (-5)^2 - (-10) = 36

Or

(-1)^2 + 5^2 - (-10) = 36

So, A is sufficient.

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Re: If x and y are integers, what is the value of (x-y)^2?  [#permalink]

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02 Jan 2018, 03:05
Question is asking value of (x-y)^2 = x^2 + y^2 - 2xy
(1) Sufficient: xy = -5, Now, one has be positive and other negative. Possible values of x and y respectively are:
(1,-5), (-1,5), (5,-1), (-5,1).
=> x^2 + y^2 - 10. Now all the possible values of x and y will give same answer for x^2+y^2.
(2) Insufficient: No data about x and y is given.
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Re: If x and y are integers, what is the value of (x-y)^2?  [#permalink]

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04 Mar 2019, 04:04
DHAR wrote:
If x and y are integers, what is the value of (x-y)^2?

Statement1: The product of x and y is -5.
Statement2: x>y

#1
x& y can be (-1,5) & ( 5,-1)
which would always give (x-y)^2 = 36
sufficient
#2
x>y
value of x & y not know
IMO A
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Re: If x and y are integers, what is the value of (x-y)^2?   [#permalink] 04 Mar 2019, 04:04
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# If x and y are integers, what is the value of (x-y)^2?

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