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If x # y = –1, which of the following could be true?

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If x # y = –1, which of the following could be true?  [#permalink]

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New post 14 Sep 2011, 05:48
1
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00:00
A
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D
E

Difficulty:

  45% (medium)

Question Stats:

60% (01:34) correct 40% (01:32) wrong based on 83 sessions

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x#y= (x−y)^2, if x>y
x#y= x+\(y/4\), if x≤y

If x # y = –1, which of the following could be true?

I. x=y
II. x>y
III. x<y

(A) I only
(B) II only
(C) III only
(D) I and III only
(E) I, II, and III

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Re: If x # y = –1, which of the following could be true?  [#permalink]

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New post 14 Sep 2011, 07:09
jamifahad wrote:
As always, post your timing for below question, if possible.

x#y= (x−y)^2, if x>y
x#y= x+\(y/4\), if x≤y

If x # y = –1, which of the following could be true?
I. x=y
II. x>y
III. x<y
(A) I only
(B) II only
(C) III only
(D) I and III only
(E) I, II, and III


(2:05)

A square can never be -ve, ruled out II.

For x=y;

x+x/4=-1; 5x=-4; x=-4/5. Possible

For x>y
x+y/4=-1

x=-1-y/4=-(y+4)/4; y=-4, x=0. Possible.

Ans: "D"
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Re: If x # y = –1, which of the following could be true?  [#permalink]

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New post 14 Sep 2011, 07:25
1
fluke wrote:
For x>y
x+y/4=-1

x=-1-y/4=-(y+4)/4; y=-4, x=0. Possible.


This should be x<y.
Other than that flawless. :lol:

This custom character sometimes puzzles me.
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Re: If x # y = –1, which of the following could be true?  [#permalink]

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New post 14 Sep 2011, 07:39
jamifahad wrote:
fluke wrote:
For x>y
x+y/4=-1

x=-1-y/4=-(y+4)/4; y=-4, x=0. Possible.


This should be x<y.
Other than that flawless. :lol:

This custom character sometimes puzzles me.


That's right. thanks
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Re: If x # y = –1, which of the following could be true?  [#permalink]

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New post 14 Sep 2011, 13:16
1
Time: 1:00 min.

Approach -
Since, x # y = –1
=> x#y= (x−y)^2, if x>y - This equation is not possible becasue any square will yield positive value.
=> x#y= x+y/4, if x≤y - This equation is only possible and as it says - x≤y, Hence - D.

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Re: If x # y = –1, which of the following could be true?  [#permalink]

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New post 17 Aug 2017, 21:58
x#y = (x-y)^2 --> this rules out a -ve value (and option which says x > y; becz square can't be -ve)
so x#y = -1; we have to consider next equation --which says x < equal to y

if x+y/4= -1 --> x+y = -4 => either x = y (-2 and -2) or x less than y (y is 0; x is -4)
Thus I and III
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Re: If x # y = –1, which of the following could be true?  [#permalink]

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Re: If x # y = –1, which of the following could be true? &nbs [#permalink] 28 Sep 2018, 09:36
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