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If x – y = p, then 2x^2 − 4xy + 2y^2 =
[#permalink]
Updated on: 08 Jul 2019, 00:56
Updated on: 08 Jul 2019, 00:56
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A
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Difficulty:
25%
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Question Stats:
74% (01:06) correct
26%
(01:04)
wrong
based on 332
sessions
If \(x – y = p\), then \(2x^2 − 4xy + 2y^2 =\)
(A) p
(B) 2p
(C) 4p
(D) p^2
(E) 2p^2
(A) p
(B) 2p
(C) 4p
(D) p^2
(E) 2p^2
Source: Nova GMAT
Difficulty Level: 600
Difficulty Level: 600
Originally posted by Bunuel on 20 May 2017, 06:54.
Last edited by Sajjad1994 on 08 Jul 2019, 00:56, edited 2 times in total.
Last edited by Sajjad1994 on 08 Jul 2019, 00:56, edited 2 times in total.
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Joined: 12 Sep 2015
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Location: Canada
Re: If x – y = p, then 2x^2 − 4xy + 2y^2 =
[#permalink]
20 May 2017, 07:21
20 May 2017, 07:21
2
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Top Contributor
Bunuel wrote:
If \(x – y = p\), then \(2x^2 − 4xy + 2y^2 =\)
(A) p
(B) 2p
(C) 4p
(D) p^2
(E) 2p^2
(A) p
(B) 2p
(C) 4p
(D) p^2
(E) 2p^2
Given: x – y = p
2x² − 4xy + 2y² = 2(x² − 2xy + y²)
= 2(x - y)²
= 2(p)²
Answer:
Cheers,
Brent
General Discussion
Re: If x – y = p, then 2x^2 − 4xy + 2y^2 =
[#permalink]
20 May 2017, 07:23
20 May 2017, 07:23
Given : \((X-Y) = p\)
Squaring both sides we have -
\(X^2+Y^2-2XY = P^2\)
Needed: \(2X^2+2Y^2-4XY = ?\)
\(2X^2+2Y^2-4XY = (X^2+Y^2-2XY )+ (X^2+Y^2-2XY)\), Substituting we get
\(P^2+P^2 = 2P^2\)
Answer choice: E
Squaring both sides we have -
\(X^2+Y^2-2XY = P^2\)
Needed: \(2X^2+2Y^2-4XY = ?\)
\(2X^2+2Y^2-4XY = (X^2+Y^2-2XY )+ (X^2+Y^2-2XY)\), Substituting we get
\(P^2+P^2 = 2P^2\)
Answer choice: E
