Last visit was: 27 Jul 2024, 00:34 It is currently 27 Jul 2024, 00:34
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
Tags:
Show Tags
Hide Tags
avatar
Intern
Intern
Joined: 15 Oct 2009
Posts: 10
Own Kudos [?]: 10 [10]
Given Kudos: 0
Send PM
Most Helpful Reply
Math Expert
Joined: 02 Sep 2009
Posts: 94619
Own Kudos [?]: 644228 [6]
Given Kudos: 86770
Send PM
General Discussion
User avatar
Manager
Manager
Joined: 09 Jun 2010
Posts: 80
Own Kudos [?]: 357 [1]
Given Kudos: 1
Send PM
User avatar
Manager
Manager
Joined: 14 Jun 2010
Posts: 130
Own Kudos [?]: 78 [0]
Given Kudos: 7
Send PM
Re: Odd or not [#permalink]
The answer should be C...
the Q asks if y(z+1) is odd , in other words it asks if Y is odd and Z is even ( Z+1) is odd ONLY when Z is even.
Thus we have C, points 1 and 2 give the info required!
User avatar
Intern
Intern
Joined: 06 Sep 2010
Posts: 5
Own Kudos [?]: 2 [0]
Given Kudos: 0
Send PM
Re: Odd or not [#permalink]
Answer - C

For y*(z + 1) to be Odd..the product of y and (z+1) has to be odd..It could happen in only one way when both the terms are odd(like 3*3=9).
1.) When y is odd - This will only give us one part of the answer since nature of z is unknown.Hence,INSUFFICIENT
2.) When z is even - This is also INSUFFICIENT coz nature of y is unknown.

On combining both cases,we can conclude that that when z is added to 1,it will become an odd number and when multiplied by an odd number y,it will always give an odd value.

Hence,answer should be C
User avatar
Manager
Manager
Joined: 04 Aug 2010
Posts: 54
Own Kudos [?]: 53 [1]
Given Kudos: 15
Send PM
Re: Odd or not [#permalink]
1
Kudos
If y and z are integers, is y*(z + 1) odd?

(1) y is odd
(2) z is even

Basically there are two conditions where you can answer if a product is odd:
either (a) both terms are odd - THEN product would be odd
or (b) one of the terms are even - THEN product would be even

Evaluate (1) y is odd
- According to condition (a), we don't know if (z + 1) is odd too.
- INSUFFICIENT

Evaluate (2) z is even
- Which means term (z + 1) is odd
- According to condition (a), we don't know if y is odd too.
- INSUFFICIENT

Evaluate (1) + (2)
- (z + 1) is odd AND y is odd
- SUFFICIENT to conclude that the product of the 2 terms is odd

Ans C
avatar
Intern
Intern
Joined: 15 Oct 2009
Posts: 10
Own Kudos [?]: 10 [0]
Given Kudos: 0
Send PM
Re: Odd or not [#permalink]
anticipation wrote:
If y and z are integers, is y*(z + 1) odd?

(1) y is odd
(2) z is even

OA: C

Why can't i plugin either of them as zero ? In that case, OA should be E. Any inputs to correct my thought process would be great ?



Thanks everyone for the solution. The key here is to know that zero is even.
Pays to know the parity of zero.
User avatar
Manager
Manager
Joined: 17 Nov 2009
Posts: 204
Own Kudos [?]: 273 [0]
Given Kudos: 17
Send PM
Re: Odd or not [#permalink]
anticipation wrote:
If y and z are integers, is y*(z + 1) odd?

(1) y is odd
(2) z is even

OA: C

Why can't i plugin either of them as zero ? In that case, OA should be E. Any inputs to correct my thought process would be great ?


Rephrase as:

Is Y odd and Z even?

Logic: O*O=Odd.
since z+1 should be odd Z should be even.

st 1: answers only 1 part of what is needed the Y part
st 2: answers only 1 part of what is needed the Z part

Together I have all I need on Y and Z
User avatar
Manager
Manager
Joined: 17 Nov 2009
Posts: 204
Own Kudos [?]: 273 [0]
Given Kudos: 17
Send PM
Re: Odd or not [#permalink]
Could this be a 700 level? Does not seem like the regular 700 questions
User avatar
Manager
Manager
Joined: 19 Sep 2010
Posts: 103
Own Kudos [?]: 235 [0]
Given Kudos: 18
Send PM
Re: Odd or not [#permalink]
No..even i don't rate it as a 700 level question . I gave few MGMAT tests . The 700 level there was pretty tough , more
calculation oriented and time consuming.
User avatar
VP
VP
Joined: 02 Jul 2009
Status:mission completed!
Posts: 1139
Own Kudos [?]: 2139 [1]
Given Kudos: 622
GPA: 3.77
Send PM
Re: Odd or not [#permalink]
1
Kudos
agnok wrote:
Could this be a 700 level? Does not seem like the regular 700 questions


no way. It is max of 600 level.

To solve just plug in even numbers including 0 {0;2} and few odd {-1;1;3} you will see that in any of cases the result will be odd.

No chances for us after Bunuel's excellent explanations.
User avatar
Manager
Manager
Joined: 19 Sep 2008
Status:Please do not forget to give kudos if you like my post
Posts: 69
Own Kudos [?]: 206 [0]
Given Kudos: 257
Location: United States (CA)
Send PM
Re: If y and z are integers, is y*(z + 1) odd? (1) y is odd (2) [#permalink]
With DS always spend 10 second stop and write down what is being asked.
Here we are asked y*(z + 1) odd?
Only way we can say this is by know whether y and z are odd/even.

1. NS - we don't know about z.
2. NS - we don't know about y.

1&2: S - have all the info to answer.

Answer: C


anticipation wrote:
If y and z are integers, is y*(z + 1) odd?

(1) y is odd
(2) z is even

OA: C

Why can't i plugin either of them as zero ? In that case, OA should be E. Any inputs to correct my thought process would be great ?
GMAT Club Bot
Re: If y and z are integers, is y*(z + 1) odd? (1) y is odd (2) [#permalink]
Moderator:
Math Expert
94619 posts