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Re: In an increasing sequence, the difference between any two successive [#permalink]
Correct me if I'm wrong - I think this question is flawed as the first term could have various values.

Option 1 (apparently the correct answer)
Let first term be a
(51-4a)+(51-2a)+51=135; a=3

Option 2
Let first term be a
a+3a+5a=135; a=15

Option 3
let first term be a
51=a+4a; a=10.2

Option 4
Let first term be a
a+3a+51=135; a=21
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In an increasing sequence, the difference between any two successive [#permalink]
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Solution


Given:
    • In an increasing sequence, d = 2a
    • S is a set of 3 successive numbers in this sequence
    • Largest number in S = 51, and sum of the three numbers in S = 135

To find:
    • The \(10^{th}\) term of this sequence

Approach and Working:
    • Sum of the three numbers in S = 51 + 51 - d + 51 – 2d = 135
      o Implies, 153 – 3d = 135
      o Thus, d = 6

    • \(t_{10} = a + 9d = \frac{d}{2} + 9d = 57\)

Hence, the correct answer is Option B

Answer: B

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Re: In an increasing sequence, the difference between any two successive [#permalink]
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: In an increasing sequence, the difference between any two successive [#permalink]
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