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In the figure below, O is the center of the circle that has a radius o

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In the figure below, O is the center of the circle that has a radius o  [#permalink]

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New post 05 Oct 2018, 00:09
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A
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C
D
E

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Question Stats:

96% (01:08) correct 4% (02:12) wrong based on 29 sessions

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In the figure below, O is the center of the circle that has a radius of 2 units. If the area of the sector containing the angle p° is π/2, what is the value of p in degrees?
Image


(A) 15.0
(B) 30.0
(C) 45.0
(D) 60.0
(E) 75.0

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Re: In the figure below, O is the center of the circle that has a radius o  [#permalink]

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New post 05 Oct 2018, 00:17
R= 2
(Theta/360)*pi*r^2 = pi/2

Theta = 45°
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Re: In the figure below, O is the center of the circle that has a radius o  [#permalink]

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New post 06 Oct 2018, 16:31
Formula to calculate area of sector, angle of sector and length of arc

\(\frac{Angle at arc}{360}\) = \(\frac{area of sector}{area of circle}\) = \(\frac{length of Arc}{2\pi r}\)

We will use this \(\frac{Angle at arc}{360}\) = \(\frac{area of sector}{area of circle}\)

\(\frac{p^o}{360}\) = \(\frac{\pi}{2}\)*\(\frac{1}{2 \pi 2}\)

On simplification we get \(p^o = 45^o\)

* application of formula tag replaces spaces between strings. Don't know how to correct this.


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Re: In the figure below, O is the center of the circle that has a radius o   [#permalink] 06 Oct 2018, 16:31
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