Last visit was: 17 Jun 2024, 00:05 It is currently 17 Jun 2024, 00:05
Toolkit
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

# In the x-y coordinate plane, lines J, K

SORT BY:
Tags:
Show Tags
Hide Tags
GMAT Club Legend
Joined: 12 Sep 2015
Posts: 6814
Own Kudos [?]: 30567 [37]
Given Kudos: 799
GMAT Club Legend
Joined: 12 Sep 2015
Posts: 6814
Own Kudos [?]: 30567 [6]
Given Kudos: 799
General Discussion
Retired Moderator
Joined: 25 Nov 2015
Status:Preparing for GMAT
Posts: 966
Own Kudos [?]: 2012 [1]
Given Kudos: 751
Location: India
GPA: 3.64
RC & DI Moderator
Joined: 02 Aug 2009
Status:Math and DI Expert
Posts: 11444
Own Kudos [?]: 33518 [4]
Given Kudos: 317
In the x-y coordinate plane, lines J, K [#permalink]
3
Kudos
1
Bookmarks
GMATPrepNow wrote:
Line J: 4x - 7 = 6y
Line K: 6y + 3x = -2
Line L: 2x = 5 - y

In the x-y coordinate plane, lines J, K and L are defined by the above equations.
Point B is the point of intersection of lines J and K. Point C is the point of intersection of lines K and L.
What is the slope of line segment BC?

A) -3/2
B) -2/3
C) -1/2
D) 1/2
E) 2/3

Great question...
Answer is right there staring at you if you understand it

A point, B ,is at intersection of line J and K and another point, C, is at intersection of K and L.. so points B and C are on line K
When you join B and C, it is nothing but a part of line K..
So slope will be same as that of line K..
$$6y+3x=-2........6y=-3x-2......y=-\frac{3x}{6} -\frac{2}{6}$$
Slope is $$-\frac{3}{6}=\frac{-1}{2}$$

C

Also if you do not get this, other way is..
Take lines J and K
Line J: 4x - 7 = 6y
Line K: 6y + 3x = -2
Two equation two variables, so you will get value of X and y of B
Similarly of C from line K and L..
Slope will be $$\frac{y_B-y_C}{x_B-x_C}$$
You will get answer as -1/2

C
Attachments

PicsArt_07-30-10.08.00.jpg [ 42.81 KiB | Viewed 5313 times ]

Non-Human User
Joined: 09 Sep 2013
Posts: 33616
Own Kudos [?]: 838 [0]
Given Kudos: 0
Re: In the x-y coordinate plane, lines J, K [#permalink]
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Re: In the x-y coordinate plane, lines J, K [#permalink]
Moderator:
Math Expert
93697 posts