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In the xy-plane, if line k has negative slope and passes

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Re: In the xy-plane, if line k has negative slope and passes [#permalink]

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New post 04 Mar 2013, 04:38
slope and algebraic

I want to follow this posting.

this type of hard question appear in gmatprep but dose not appear in og.
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Re: In the xy-plane, if line k has negative slope and passes [#permalink]

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New post 04 Mar 2013, 04:47
this type of question appear infrequently and so become hard questions.

never use drawings. use algebraic
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Re: In the xy-plane, if line k has negative slope and passes [#permalink]

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New post 07 Jun 2013, 00:43
GMATMadeeasy wrote:
In the xy-plane, if line k has negative slope and passes through the point (-5,r) , is the x-intercept of line k positive?

(1) The slope of line k is -5.
(2) r > 0


the answer is E only because : as per your assumption you took x intercept as x.but it can also be negative try it with -x we cannot determine the sign of x intercept.if x intercept is (-x,0) then slope m=r-0/-5+x.
and x=r+5m/m..

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Re: In the xy-plane, if line k has negative slope and passes [#permalink]

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New post 05 Dec 2014, 23:09
(1) the slope of line k is -5 => we know for each unit of "run" the line should have 5 units of "fall" => the x-intercept to be positive we should have r>25 but here the value of r is not clear => insufficient.
(2) r>0, same as (1) the value of r is not clear also we don't know the slope => insufficient.
(1) & (2): we know the slope is -5 and r>0 but r can be greater than 25 or less than it. => insufficient.

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Re: In the xy-plane, if line k has negative slope and passes [#permalink]

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New post 24 Dec 2015, 07:56
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Re: In the xy-plane, if line k has negative slope and passes [#permalink]

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New post 25 Sep 2016, 04:29
GMATMadeeasy wrote:
In the xy-plane, if line k has negative slope and passes through the point (-5,r) , is the x-intercept of line k positive?

(1) The slope of line k is -5.
(2) r > 0

Hi,
Can you please tell where I am wrong.
I assumed eq of line as y=mx+c.
Let x intercept be A(x,0)
At point A,
0=mx+c
=>x=-c/m
Hence, sign of x will depend on sign of c/m
Since m is negative,
i. if c<0, -c/m <0 =>x<0
ii. if c>0, -c/m >0 =>x>0

Statement 1 is not sufficient.
As per statement 2, r>0
=> -5m+c>0
=>-5m>-c
=>5m<c
=>5<c/m or c/m >5
=> both c and m have same sign i.e. m,c<0
=> x<0
=> Statement 2 is sufficient

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Re: In the xy-plane, if line k has negative slope and passes [#permalink]

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New post 23 Feb 2017, 04:56
PROMPT ANALYSIS
The equation of the will be y = r + m(x+5) where m is the slope. X intercept is -r/m -5

Superset
The answer will be either yes or no.

Translation
In order to find the answer we need:
1# Exact value of m and r
2# Equations to solve m and r

STATEMENT ANALYSIS

St 1: m = -5. For this x intercept is r/5 -5. Cannot say about the sign of the expression because r can be any real number.INSUFFICIENT. Hence option a and d eliminated.

St 2: r>0. The value of -r/m -5 will depend on the value of m, which can be any real number. INSUFFICIENT. Hence option b eliminated.

St 1&st 2: r/5 -5 will be positive for natural number r>25, these kind of constraints are not given. SO INSUFFICIENT. HEnce option c eliminated.
Option E.

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Re: In the xy-plane, if line k has negative slope and passes   [#permalink] 23 Feb 2017, 04:56

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