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In the XY-plane, the point (3, 2) is the center of a circle. The point

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In the XY-plane, the point (3, 2) is the center of a circle. The point  [#permalink]

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New post 16 Oct 2018, 03:53
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In the XY-plane, the point (3, 2) is the center of a circle. The point (−1, 2) lies inside the circle and the point (3, −4) lies outside the circle. Which of the following could be the value of r ?

(A) 5
(B) 4
(C) 3
(D) 2
(E) 1

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In the XY-plane, the point (3, 2) is the center of a circle. The point  [#permalink]

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New post 16 Oct 2018, 04:08
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Bunuel wrote:
In the XY-plane, the point (3, 2) is the center of a circle. The point (−1, 2) lies inside the circle and the point (3, −4) lies outside the circle. Which of the following could be the value of r ?

(A) 5
(B) 4
(C) 3
(D) 2
(E) 1


If a point lies inside the circle then Distance between Point and centre < Radius

If a point lies Outside the circle then Distance between Point and centre > Radius


i.e. R > distance between (3,2) and (-1,2)\(= √(-1-3)^2+(2-2)^2 = 4\)

and R < distance between (3,2) and (3,-4)\(= 6\) x co-ordinates of the two points are same i.e. distance will be same as the distance between their Y co-ordinates

i.e. r could be anything between 4 and 6

Answer: Option A
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Re: In the XY-plane, the point (3, 2) is the center of a circle. The point  [#permalink]

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New post 28 Dec 2018, 13:11
distance b/w (3,2) and (-1,2) x axis is 4
distance b/w (3,2) and (3,-4) y axis is 6
radius>4(lies inside), radius <6 (lies outside)
so, 4<r<6 i.e. 5

answer a
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Re: In the XY-plane, the point (3, 2) is the center of a circle. The point  [#permalink]

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New post 29 Dec 2018, 13:15
GMATinsight wrote:
Bunuel wrote:
In the XY-plane, the point (3, 2) is the center of a circle. The point (−1, 2) lies inside the circle and the point (3, −4) lies outside the circle. Which of the following could be the value of r ?

(A) 5
(B) 4
(C) 3
(D) 2
(E) 1


If a point lies inside the circle then Distance between Point and centre < Radius

If a point lies Outside the circle then Distance between Point and centre > Radius


i.e. R > distance between (3,2) and (-1,2)\(= √(-1-3)^2+(2-2)^2 = 4\)

and R < distance between (3,2) and (3,-4)\(= 6\) x co-ordinates of the two points are same i.e. distance will be same as the distance between their Y co-ordinates

i.e. r could be anything between 4 and 6

Answer: Option A


If you are really certain with the maths here, you only need to know that 4 < r and then the answer has to be 5 (A), due to the answer choices given
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Re: In the XY-plane, the point (3, 2) is the center of a circle. The point &nbs [#permalink] 29 Dec 2018, 13:15
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In the XY-plane, the point (3, 2) is the center of a circle. The point

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