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Hi fattty,

This question can be solved by TESTing VALUES and Number Properties.

We're told that R and S are POSITIVE INTEGERS. We're asked if (R)(S) is a multiple of 25? This is a YES/NO question.

1) R - S is a multiple of 5

This Fact tells us that EITHER both variables are multiples of 5 OR both variables are NOT multiples of 5.

IF....
R = 6
S = 1
(6)(1) = 6 and the answer to the question is NO.

IF....
R = 10
S = 5
(10)(5) = 50 and the answer to the question is YES.
Fact 1 is INSUFFICIENT

(2) (R)(S) is a multiple of 5

This Fact tells us that AT LEAST ONE of the two variables is a multiple of 5.

IF....
R = 5
S = 4
(5)(4) = 20 and the answer to the question is NO.

IF....
R = 10
S = 5
(10)(5) = 50 and the answer to the question is YES.
Fact 2 is INSUFFICIENT

Combined, we know that...
R - S is a multiple of 5
(R)(S) is a multiple of 5

From Fact 2, we know that AT LEAST one of the two variables is a multiple of 5. From the Fact 1, we know that IF one of the variables is a multiple of 5, then the other one MUST be also. Combining these two Facts proves that BOTH variables are multiples of 5; when you multiply two multiples of 5 together, you end up with a larger number that is a multiple of 25. Thus, the answer to the question is ALWAYS YES.
Combined, SUFFICIENT

Final Answer:
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1. r-s = multiple of 5.
we can have 2 multiples of 5, then rs will be divisible by 25
or we can have r=7 and s=2. in this case - no.

2. rs=multiple of 5.
r=1, s=5 -> not multiple of 25.
r=5, s=5 -> multiple of 25
2 alone not sufficient.

1+2
rs multiple of 5
r-s is a multiple of 5
it must be true that both r and s are multiple of 5.

C
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Still not clear. Can someone please elaborate this for me.

TIA
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AmritaSarkar89
Still not clear. Can someone please elaborate this for me.

TIA

Let me try helping you out.

We are asked if rs = 25 * k , where k is a positive integer. ( r and s both are given as positive integers)

Now,

Statement 1 : r - s = 5k' ; This is possible when r= 10 and s = 5, in that case rs will be a multiple of 5. But it is possible when r = 7 and s =2, in that case rs will not be a multiple of 5. Hence, insufficient.

Statement 2 : rs is a multiple of 5. It may happen rs = 10 ( Not a multiple of 25) or rs = 25 ( A multiple of 5) Hence, insufficient.

Combining, for rs to be a multiple of 5, we need to have atleast one of r or s a multiple of 5. And we have seen in statement 1 that when one is a multiple of 5 the other should also be a multiple of 5 to get the difference a multiple of 5. Hence, Sufficient.
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can zero be a multiple of any integer other than zero?
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PrinceVegeta
can zero be a multiple of any integer other than zero?

0 is a multiple of all integers.
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Is rs divisible by 25?
For this to happen, we need at least two factors of 5 from rs.

(1) r-s is divisible by 5.

Case 1: 10-5 = 5 --> where both numbers are divisible by 5. If any one is divisible by 5, the other has to be otherwise their subtraction won't be.

This explanation might help:
r= 5k (say)
r-s = 5m
5k-s = 5m
s = 5(k-m) = 5z
s is also a multiple of 5.

Case 2: 7-2 = 5. neither of them is a multiple of 5.

Not sufficient.

(2) rs = 5k
In this case, either r or s or both are multiples of 5. But if only one is a multiple of 5, we can't say for sure that there would be one more factor of 5, making it 25.

Not sufficient.

(1) and (2) together:
rs = 5k --> at least one of them is a multiple of 5.
As per one, either both are multiples of 5 or neither is. See explanation above.

Sufficient.
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