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Is the value of a^2 - b^2 > greater than the value of

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Is the value of a^2 - b^2 > greater than the value of  [#permalink]

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New post 29 Sep 2012, 12:21
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Re: Is the value of a^2 - b^2 > greater than the value of  [#permalink]

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New post 29 Sep 2012, 13:04
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carcass wrote:
Is the value of a^2 - b^2 greater than the value of (3a + 3b) (2a - 2b) ?

1) b < a

2) a < -1

A tricky one


The question "Is \(a^2-b^2>3(a+b)2(a-b)=6(a^2-b^2)\)?" translates to "Is \(a^2-b^2<0\)?" or "Is \(|a|<|b|\)"?

(1) We can have \(b=-7<3=a\) or \(b=3<7=a\).
Not sufficient.

(2) Obviously not sufficient, no information about \(b\).

(1) and (2) together: now \(b<a<-1\), so necessarily \(|a|<|b|\).
Sufficient.

Answer C.
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Re: Is the value of a^2 - b^2 > greater than the value of  [#permalink]

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New post 29 Sep 2012, 15:04
Hi evajager

I elaborated in this way

1) b < a the value depend on the absolute value of b (when we have a value \(n^2\) we really do not know )

2) nothing about b

1) + 2) we know that b < a < - 1 \(a^2 - b^2\) must be begative ------> 6 * negative = a big negative number ------> 6 ( \(a^2 - b^2\) ) < \(a^2 - b^2\)

Can you explain me \(a^2 - b^2 < 0\) ????

Thanks :)
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Re: Is the value of a^2 - b^2 > greater than the value of  [#permalink]

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New post 29 Sep 2012, 15:15
carcass wrote:
Hi evajager

I elaborated in this way

1) b < a the value depend on the absolute value of b (when we have a value \(n^2\) we really do not know )

2) nothing about b

1) + 2) we know that b < a < - 1 \(a^2 - b^2\) must be begative ------> 6 * negative = a big negative number ------> 6 ( \(a^2 - b^2\) ) < \(a^2 - b^2\)

Can you explain me \(a^2 - b^2 < 0\) ????

Thanks :)


\(a^2-b^2>3(a+b)2(a-b)=6(a^2-b^2)\) or \(0>5(a^2-b^2)\) which means \(0>a^2-b^2\).
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Re: Is the value of a^2 - b^2 > greater than the value of  [#permalink]

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New post 29 Sep 2012, 15:19
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Re: Is the value of a^2 - b^2 > greater than the value of  [#permalink]

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New post 07 Oct 2015, 13:29
carcass wrote:
Is the value of a^2 - b^2 greater than the value of (3a + 3b) (2a - 2b) ?

(1) b < a

(2) a < -1


Is \(a^2-b^2 > 6* (a^2 - b^2)\) ? --> Is \(5*(a^2-b^2) < 0\) ? --> Is \(5*(a-b) * (a+b) < 0\) ?

(1) Statement 1 can be written as b-a<0, which implies a-b>0. No information is given about a+b. Hence insufficient.

(2) Statement 2 is insufficient because no information is given about b

(Combined) a and b are both negative, hence we know a+b is also negative. The answer to the question stem is Yes. Answer choice C is correct.
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Re: Is the value of a^2 - b^2 > greater than the value of  [#permalink]

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New post 26 Feb 2018, 03:20
The question can be rewritten as is (a+b)(a-b)> 6(a+b)(a-b) ??

st 1) b<a they can be any number with different signs not sufficient
st 2) a<-1 we don't know anything about B not sufficient

together, we know that a<-1 and b<a so b should be also negative
(a+b) should result a negative number whereas (a-b) will be positive
if we plug in the signs to our original question:
(-)(+)> 6(-)(+) ?? yes, a negative number will be greater than that negative number multiplied by 6.
so the answer should be C
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Re: Is the value of a^2 - b^2 > greater than the value of   [#permalink] 26 Feb 2018, 03:20
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