Bunuel wrote:
Chembeti wrote:
Jolene entered an 18-month investment contract that guarantees to pay 2 percent interest at the end of 6 months, another 3 percent interest at the end of 12 months, and 4 percent interest at the end of the 18 month contract. If each interest payment is reinvested in the contract, and Jolene invested $10,000 initially, what will be the total amount of interest paid during the 18-month contract?
A. $506.00
B. $726.24
C. $900.00
D. $920.24
E. $926.24
This is very simple problem,yet need to pay attention to words in the problem
If interest were not compounded in every six months (so if interest were not earned on interest) then we would have (2+3+4)=9% simple interest earned on $10,000, which is $900. So, you can rule out A, B and C right away.
Interest earned after the first time interval: $10,000*2%=$200;
Interest earned after the second time interval: ($10,000+$200)*3%=$300+$6=$306;
Interest earned after the third time interval: ($10,000+$200+$306)*4%=$400+$8+(~$12)=~$420;
Total: 200+306+(~420)=~$926.
Answer: E.
hey thanks for this explanation ,
but just one small query may be a bit silly .
so can we solve this question by these steps are a but longer but i am just asking tom solidify my concept :
1. SI=PNR/100 so for first 6 months it should be SI=10,000*2*6/100*12=100$
2. 10,000+100$=10,100$= next 6 months = 10100*3*6/100*12=151.5
3. 10100+151.5=10251.5*4*6/100*12
is this the wrong way to solve this question??