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M and N working together, can finish a job in 6 days
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Updated on: 27 Aug 2018, 03:09
Question Stats:
93% (01:49) correct 7% (01:43) wrong based on 56 sessions
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M and N working together, can finish a job in 6 days. With the help of P, they completed the job in 4 days. If Q joined them, all 4 together would have completed the job in 3\(\frac{1}{3}\) days. If all work at their respective constant rate, then in how many days Q alone can complete the work? A. 10 B. 12 C. 15 D. 18 E. 20 To read all our articles: Must read articles to reach Q51
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M and N working together, can finish a job in 6 days
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27 Aug 2018, 02:59
EgmatQuantExpert wrote: M and N working together, can finish a job in 6 days. With the help of P, they completed the job in 4 days. If Q joined them, all 4 together would have completed the job in 31/3 days. If all work at their respective constant rate, then in how many days Q alone can complete the work? A. 10 B. 12 C. 15 D. 18 E. 20 To read all our articles: Must read articles to reach Q51All four can complete the job in 3 and 1/3 days or 10/3 , so 1 day work =3/10 All except Q can complete job in 4 days, so their 1 day work=1/4 So 1 day work of Q = 3/101/4=(1210)/40=1/20 So total work in 20 days.. E EgmatQuantExpert, how can 3 people finish faster in 4 days as compared to a situation when a fourth person joins them and now in 31/3=10 days ?????
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1) Absolute modulus : http://gmatclub.com/forum/absolutemodulusabetterunderstanding210849.html#p1622372 2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html 3) effects of arithmetic operations : https://gmatclub.com/forum/effectsofarithmeticoperationsonfractions269413.html
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Re: M and N working together, can finish a job in 6 days
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27 Aug 2018, 03:13
chetan2u wrote: All four can complete the job in 31/3 days , so 1 day work =3/31 All except Q can complete job in 4 days, so their 1 day work=1/4 EgmatQuantExpert, how can 3 people finish faster in 4 days as compared to a situation when a fourth person joins them and now in 31/3=10 days ????? It was a tagging error. It should be 3\(\frac{1}{3}\) days not 31/3. We have corrected it.
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Re: M and N working together, can finish a job in 6 days
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27 Aug 2018, 07:12
chetan2u wrote: EgmatQuantExpert wrote: M and N working together, can finish a job in 6 days. With the help of P, they completed the job in 4 days. If Q joined them, all 4 together would have completed the job in 31/3 days. If all work at their respective constant rate, then in how many days Q alone can complete the work? A. 10 B. 12 C. 15 D. 18 E. 20 To read all our articles: Must read articles to reach Q51 All four can complete the job in 3 and 1/3 days or 10/3 , so 1 day work =3/10All except Q can complete job in 4 days, so their 1 day work=1/4 So 1 day work of Q = 3/101/4=(1210)/40=1/20 So total work in 20 days.. E EgmatQuantExpert, how can 3 people finish faster in 4 days as compared to a situation when a fourth person joins them and now in 31/3=10 days ????? what is the reason you switched 10/3 to 3/10 ?
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Re: M and N working together, can finish a job in 6 days
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27 Aug 2018, 07:23
dave13 wrote: chetan2u wrote: EgmatQuantExpert wrote: M and N working together, can finish a job in 6 days. With the help of P, they completed the job in 4 days. If Q joined them, all 4 together would have completed the job in 31/3 days. If all work at their respective constant rate, then in how many days Q alone can complete the work? A. 10 B. 12 C. 15 D. 18 E. 20 To read all our articles: Must read articles to reach Q51 All four can complete the job in 3 and 1/3 days or 10/3 , so 1 day work =3/10All except Q can complete job in 4 days, so their 1 day work=1/4 So 1 day work of Q = 3/101/4=(1210)/40=1/20 So total work in 20 days.. E EgmatQuantExpert, how can 3 people finish faster in 4 days as compared to a situation when a fourth person joins them and now in 31/3=10 days ????? what is the reason you switched 10/3 to 3/10 ? dave13If someone can do a job in 10 days so each day he does 1/10 th of work.. So here also they complete the work in 10/3 days, thus in one day they can do 3/10th of work as 1/(10/3)=1*3/10=3/10 If A is doing 1/2 of the work in one day, A will complete full work in 2 days as 1/(1/2)=1*2/1=2
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1) Absolute modulus : http://gmatclub.com/forum/absolutemodulusabetterunderstanding210849.html#p1622372 2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html 3) effects of arithmetic operations : https://gmatclub.com/forum/effectsofarithmeticoperationsonfractions269413.html
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