It is currently 18 Jan 2018, 02:17

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

M02-25

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Expert Post
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 43317

Kudos [?]: 139367 [0], given: 12787

M02-25 [#permalink]

Show Tags

New post 15 Sep 2014, 23:18
Expert's post
32
This post was
BOOKMARKED
00:00
A
B
C
D
E

Difficulty:

  95% (hard)

Question Stats:

33% (01:51) correct 67% (01:48) wrong based on 235 sessions

HideShow timer Statistics

Kudos [?]: 139367 [0], given: 12787

Expert Post
3 KUDOS received
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 43317

Kudos [?]: 139367 [3], given: 12787

M02-25 [#permalink]

Show Tags

New post 15 Sep 2014, 23:18
3
This post received
KUDOS
Expert's post
9
This post was
BOOKMARKED
Official Solution:

If x and y are positive integers, is x a prime number?

(1)\(|x - 2| \lt 2 - y\). The left hand side of the inequality is an absolute value, so the least value of LHS is zero, thus \(0 \lt 2 - y\), thus \(y \lt 2\) (if \(y\) is more than or equal to 2, then \(y-2 \le{0}\) and it cannot be greater than \(|x - 2|\)). Next, since given that \(y\) is a positive integer, then \(y=1\).

So, we have that: \(|x - 2| \lt 1\), which implies that \(-1 \lt x-2 \lt 1\), or \(1 \lt x \lt 3\), thus \(x=2=prime\). Sufficient.

(2)\(x + y - 3 = |1-y|\). Since \(y\) is a positive integer, then \(1-y \le {0}\), thus \(|1-y|=-(1-y)\). So, we have that \(x + y - 3 = -(1-y)\), which gives \(x=2=prime\). Sufficient.


Answer: D
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Kudos [?]: 139367 [3], given: 12787

Manager
Manager
User avatar
B
Joined: 11 Sep 2013
Posts: 159

Kudos [?]: 155 [0], given: 262

Concentration: Finance, Finance
Re: M02-25 [#permalink]

Show Tags

New post 27 Nov 2014, 11:44
[quote="Bunuel"]Official Solution:


(if \(y\) is more than or equal to 2, then \(y-2 \le{0}\)


Since \(y\) is a positive integer, then \(1-y \le {0}\),

I have not understood the above two things. Could you please help me on this? How can we get these equation?

Kudos [?]: 155 [0], given: 262

Expert Post
1 KUDOS received
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 43317

Kudos [?]: 139367 [1], given: 12787

M02-25 [#permalink]

Show Tags

New post 28 Nov 2014, 04:33
1
This post received
KUDOS
Expert's post
1
This post was
BOOKMARKED
Raihanuddin wrote:
Bunuel wrote:
Official Solution:


(if \(y\) is more than or equal to 2, then \(y-2 \le{0}\)


Since \(y\) is a positive integer, then \(1-y \le {0}\),

I have not understood the above two things. Could you please help me on this? How can we get these equation?


I tried to explain this in my solution.

1. (1) \(|x - 2| \lt 2 - y\). The left hand side of the inequality is an absolute value, so the least value of LHS is zero, thus \(0 \lt 2 - y\), thus \(y \lt 2\).

2. For (2): we know that y is a positive integer 1, 2, 3, ... so 1 - y must be less than or equal to 0.
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Kudos [?]: 139367 [1], given: 12787

Intern
Intern
avatar
Status: Brushing up rusted Verbal....
Joined: 30 Oct 2013
Posts: 17

Kudos [?]: 9 [0], given: 29

Location: India
Schools: AGSM '16
GMAT Date: 11-30-2014
GPA: 3.96
WE: Information Technology (Computer Software)
GMAT ToolKit User
Re: M02-25 [#permalink]

Show Tags

New post 28 Nov 2014, 05:30
positive integer means we should not consider zero??

Kudos [?]: 9 [0], given: 29

Manager
Manager
User avatar
B
Joined: 11 Sep 2013
Posts: 159

Kudos [?]: 155 [0], given: 262

Concentration: Finance, Finance
Re: M02-25 [#permalink]

Show Tags

New post 28 Nov 2014, 05:45
sudd1 wrote:
positive integer means we should not consider zero??


Yes, positive integers can't be zero. It will start from 1

Kudos [?]: 155 [0], given: 262

Expert Post
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 43317

Kudos [?]: 139367 [0], given: 12787

Re: M02-25 [#permalink]

Show Tags

New post 28 Nov 2014, 07:25

Kudos [?]: 139367 [0], given: 12787

Intern
Intern
avatar
Joined: 15 Feb 2015
Posts: 5

Kudos [?]: 6 [0], given: 319

Location: United States
Concentration: Finance, Strategy
GMAT ToolKit User Premium Member
Re: M02-25 [#permalink]

Show Tags

New post 20 Apr 2015, 22:00
Bunuel, from what I understand about absolute values, the number/expression within the absolute number sign could either be positive or negative (just like the way the square root of a number could either be positive or negative), so I didn't understand how the least value in the LHS is zero. Please explain? Thanks

Kudos [?]: 6 [0], given: 319

Expert Post
1 KUDOS received
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 43317

Kudos [?]: 139367 [1], given: 12787

Re: M02-25 [#permalink]

Show Tags

New post 21 Apr 2015, 04:25
1
This post received
KUDOS
Expert's post
2
This post was
BOOKMARKED
Kigunda wrote:
Bunuel, from what I understand about absolute values, the number/expression within the absolute number sign could either be positive or negative (just like the way the square root of a number could either be positive or negative), so I didn't understand how the least value in the LHS is zero. Please explain? Thanks


I think this is explained here: m02-183573.html#p1448632

The point is that |some expression| >= 0. So, when we have |some expression| = x, it means that x must be more than or equal to 0 too.

Also, the square root of a number cannot be negative \(\sqrt{4}=2\), not +/-2.

When the GMAT provides the square root sign for an even root, such as a square root, fourth root, etc. then the only accepted answer is the positive root. That is:

\(\sqrt{9} = 3\), NOT +3 or -3;
\(\sqrt[4]{16} = 2\), NOT +2 or -2;

Notice that in contrast, the equation \(x^2 = 9\) has TWO solutions, +3 and -3. Because \(x^2 = 9\) means that \(x =-\sqrt{9}=-3\) or \(x=\sqrt{9}=3\).

Theory on Number Properties: math-number-theory-88376.html
Tips on Numper Properties: number-properties-tips-and-hints-174996.html

All DS Number Properties Problems to practice: search.php?search_id=tag&tag_id=38
All PS Number Properties Problems to practice: search.php?search_id=tag&tag_id=59

_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Kudos [?]: 139367 [1], given: 12787

Intern
Intern
avatar
Joined: 14 Oct 2015
Posts: 37

Kudos [?]: 19 [0], given: 0

GMAT 1: 640 Q45 V33
Re M02-25 [#permalink]

Show Tags

New post 16 Oct 2015, 07:18
I think this is a high-quality question and I agree with explanation. This question is the same as M28-58

Kudos [?]: 19 [0], given: 0

Intern
Intern
avatar
B
Joined: 26 Jul 2014
Posts: 15

Kudos [?]: 7 [0], given: 23

Schools: Kellogg PT '17
Premium Member
Re: M02-25 [#permalink]

Show Tags

New post 20 Nov 2015, 18:38
Can someone help me understand this part in detail

2)x+y−3=|1−y|. Since y is a positive integer, then 1−y≤0, thus |1−y|=−(1−y).

why we are not considering the |1−y|=(1−y) ??

Kudos [?]: 7 [0], given: 23

Expert Post
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 43317

Kudos [?]: 139367 [0], given: 12787

Re: M02-25 [#permalink]

Show Tags

New post 21 Nov 2015, 01:46
Expert's post
1
This post was
BOOKMARKED
sajib2126 wrote:
Can someone help me understand this part in detail

2)x+y−3=|1−y|. Since y is a positive integer, then 1−y≤0, thus |1−y|=−(1−y).

why we are not considering the |1−y|=(1−y) ??


Let me ask you if y is a positive integer what are the possible values of 1 - y ?
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Kudos [?]: 139367 [0], given: 12787

Intern
Intern
avatar
Joined: 29 Apr 2015
Posts: 27

Kudos [?]: 70 [0], given: 1

Location: Russian Federation
GMAT 1: 710 Q48 V38
GPA: 4
GMAT ToolKit User
Re: M02-25 [#permalink]

Show Tags

New post 23 Dec 2015, 08:43
Bunuel wrote:
If \(x\) and \(y\) are positive integers, is \(x\) a prime number?


(1) \(|x - 2| \lt 2 - y\)

(2) \(x + y - 3 = |1-y|\)



I've solved this problem in a little different way.

1) |x - 2| < 2 - y It means
-(2 - y) < x - 2 < 2 - y =>
y - 2 < x - 2 < 2 - y =>
y < x < 4 - y

Try pick up numbers. It's said that x and y are positive integers.
Let's say y is 1, then x could be 2 or 3.
y can't be 2, 3 or any other integer, because it violates the inequality.
In both cases, whether x is 2 or 3, x is a prime number. Therefore, first statement is sufficient.

2) x + y - 3 = |1 - y| It means
x + y - 3 = 1 - y or x + y - 3 = -(1 - y), x + y - 3 = y - 1
x = 4 - 2y or x = 2 . 2 is a prime number. Therefore, second statement is sufficient too.

Thus, correct answer is D: both statements are sufficient.

Kudos [?]: 70 [0], given: 1

Manager
Manager
User avatar
B
Joined: 18 Mar 2015
Posts: 102

Kudos [?]: 4 [0], given: 113

Location: India
Schools: ISB '19
GMAT 1: 600 Q47 V26
GPA: 3.59
Reviews Badge
Re M02-25 [#permalink]

Show Tags

New post 17 Jul 2016, 09:37
I think this the explanation isn't clear enough, please elaborate. for option 1 my logic is
since x is a positive integer, lx-2l>0, therefore
x-2<2-y
x+y<4
so, X can be 1 or 2, cannot determine
can someone correct me, if my logic is wrong?

Kudos [?]: 4 [0], given: 113

Expert Post
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 43317

Kudos [?]: 139367 [0], given: 12787

Re: M02-25 [#permalink]

Show Tags

New post 17 Jul 2016, 09:40
Expert's post
1
This post was
BOOKMARKED
r19 wrote:
I think this the explanation isn't clear enough, please elaborate. for option 1 my logic is
since x is a positive integer, lx-2l>0, therefore
x-2<2-y
x+y<4
so, X can be 1 or 2, cannot determine
can someone correct me, if my logic is wrong?


(1) \(|x - 2| \lt 2 - y\). The left hand side of the inequality is an absolute value, so the least value of LHS is zero, thus \(0 \lt 2 - y\), thus \(y \lt 2\).
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Kudos [?]: 139367 [0], given: 12787

Intern
Intern
avatar
Joined: 25 May 2014
Posts: 9

Kudos [?]: 12 [0], given: 2

GMAT 1: 660 Q47 V35
Reviews Badge
Re: M02-25 [#permalink]

Show Tags

New post 04 Sep 2016, 03:28
then 1−y≤01−y≤0, thus |1−y|=−(1−y)|1−y|=−(1−y)


How is that |1−y|=−(1−y)|1−y|=−(1−y) always?

How about the case when y =1 , shouldn't it be (1-y) only then??

Kudos [?]: 12 [0], given: 2

Expert Post
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 43317

Kudos [?]: 139367 [0], given: 12787

Re: M02-25 [#permalink]

Show Tags

New post 04 Sep 2016, 04:06
victoraditya wrote:
then 1−y≤01−y≤0, thus |1−y|=−(1−y)|1−y|=−(1−y)


How is that |1−y|=−(1−y)|1−y|=−(1−y) always?

How about the case when y =1 , shouldn't it be (1-y) only then??


Why? What would be -(1-y) and |1-y| for y=1?
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Kudos [?]: 139367 [0], given: 12787

Intern
Intern
avatar
Joined: 25 May 2014
Posts: 9

Kudos [?]: 12 [0], given: 2

GMAT 1: 660 Q47 V35
Reviews Badge
Re: M02-25 [#permalink]

Show Tags

New post 04 Sep 2016, 05:12
Hi Bunnel,
got it.. so is it that for <=0 inequalities, we can always take the negative?

Thanks.

Kudos [?]: 12 [0], given: 2

Intern
Intern
avatar
B
Joined: 23 Jun 2016
Posts: 17

Kudos [?]: 1 [0], given: 36

GMAT ToolKit User
M02-25 [#permalink]

Show Tags

New post 12 Dec 2016, 19:04
Bunuel wrote:
Official Solution:

If x and y are positive integers, is x a prime number?

(1)\(|x - 2| \lt 2 - y\). The left hand side of the inequality is an absolute value, so the least value of LHS is zero, thus \(0 \lt 2 - y\), thus \(y \lt 2\) (if \(y\) is more than or equal to 2, then \(y-2 \le{0}\) and it cannot be greater than \(|x - 2|\)). Next, since given that \(y\) is a positive integer, then \(y=1\).

So, we have that: \(|x - 2| \lt 1\), which implies that \(-1 \lt x-2 \lt 1\), or \(1 \lt x \lt 3\), thus \(x=2=prime\). Sufficient.

(2)\(x + y - 3 = |1-y|\). Since \(y\) is a positive integer, then \(1-y \le {0}\), thus \(|1-y|=-(1-y)\). So, we have that \(x + y - 3 = -(1-y)\), which gives \(x=2=prime\). Sufficient.


Answer: D



Thanks for the solution. But, i can`t understand one point. In statement 1, you mentioned if y is more than or equal to 2, then y−2≤0y−2≤0 and it cannot be greater than |x−2||x−2|. Could you please explain this point in more detail?

Thanks in advance.

Kudos [?]: 1 [0], given: 36

Expert Post
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 43317

Kudos [?]: 139367 [0], given: 12787

Re: M02-25 [#permalink]

Show Tags

New post 13 Dec 2016, 00:55
jahidhassan wrote:
Bunuel wrote:
Official Solution:

If x and y are positive integers, is x a prime number?

(1)\(|x - 2| \lt 2 - y\). The left hand side of the inequality is an absolute value, so the least value of LHS is zero, thus \(0 \lt 2 - y\), thus \(y \lt 2\) (if \(y\) is more than or equal to 2, then \(y-2 \le{0}\) and it cannot be greater than \(|x - 2|\)). Next, since given that \(y\) is a positive integer, then \(y=1\).

So, we have that: \(|x - 2| \lt 1\), which implies that \(-1 \lt x-2 \lt 1\), or \(1 \lt x \lt 3\), thus \(x=2=prime\). Sufficient.

(2)\(x + y - 3 = |1-y|\). Since \(y\) is a positive integer, then \(1-y \le {0}\), thus \(|1-y|=-(1-y)\). So, we have that \(x + y - 3 = -(1-y)\), which gives \(x=2=prime\). Sufficient.


Answer: D



Thanks for the solution. But, i can`t understand one point. In statement 1, you mentioned if y is more than or equal to 2, then y−2≤0y−2≤0 and it cannot be greater than |x−2||x−2|. Could you please explain this point in more detail?

Thanks in advance.


If y is greater than 2 then the right hand side of the inequality (2-y) becomes negative. The left hand side if the inequality is an absolute value (|x - 2|) which cannot be negative, thus the inequality (\(|x - 2| \lt 2 - y\)) will not hold true. Please re-read the discussion above.
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Kudos [?]: 139367 [0], given: 12787

Re: M02-25   [#permalink] 13 Dec 2016, 00:55

Go to page    1   2    Next  [ 29 posts ] 

Display posts from previous: Sort by

M02-25

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  

Moderators: chetan2u, Bunuel



GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.