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Re: M09-08 [#permalink]
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If x and y are positive integers such that \frac{x}{y}= 2.625, which of the following could be the remainder when x is divided by y?

Sol:
frac{x}{y}= 2.625
The formula to calculate remainder if X/Y = a.bcd is to multiply denominator of LHS to post decima l part of RHS

Rem = y * 0.625
= y * 625/1000
= y * 5/8
which is multiple of 5 and only option which is multiple of 5 in the options is 5.
So 5 is the answer
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Re: M09-08 [#permalink]
Can i mark 5 as the answer choice considering that 0.625 will be a multiple of 5 only since it is ending with 5?
Thanks
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Re: M09-08 [#permalink]
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pratiksingh023 wrote:
Can i mark 5 as the answer choice considering that 0.625 will be a multiple of 5 only since it is ending with 5?
Thanks


No. If it were 2.15 instead of 2.625, then we'd get \(\frac{x}{y}=2.15=2\frac{3}{20}=2+\frac{3}{20}\), and in this case r would need to be a multiple of 3, not necessarily a multiple of 5.
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Re: M09-08 [#permalink]
This post by VeritasKarishma explains it perfectly.
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Re: M09-08 [#permalink]
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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Re M09-08 [#permalink]
I think this is a high-quality question and I agree with explanation. Can anyone pls tell me how to convert decimals into improper fractions?
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Re: M09-08 [#permalink]
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Vikramaditya00 wrote:
I think this is a high-quality question and I agree with explanation. Can anyone pls tell me how to convert decimals into improper fractions?

­Check here:

https://gmatclub.com/forum/math-number- ... 88376.html

Hope this helps.
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Re: M09-08 [#permalink]
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