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# M09-08

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Math Expert
Joined: 02 Sep 2009
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Math Expert
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Manager
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Posts: 110
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Location: India
Concentration: Technology, Marketing
Manager
Joined: 20 Jan 2014
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Location: India
Concentration: Technology, Marketing
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If x and y are positive integers such that \frac{x}{y}= 2.625, which of the following could be the remainder when x is divided by y?

Sol:
frac{x}{y}= 2.625
The formula to calculate remainder if X/Y = a.bcd is to multiply denominator of LHS to post decima l part of RHS

Rem = y * 0.625
= y * 625/1000
= y * 5/8
which is multiple of 5 and only option which is multiple of 5 in the options is 5.
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GMAT 1: 640 Q49 V28
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Can i mark 5 as the answer choice considering that 0.625 will be a multiple of 5 only since it is ending with 5?
Thanks
Math Expert
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pratiksingh023 wrote:
Can i mark 5 as the answer choice considering that 0.625 will be a multiple of 5 only since it is ending with 5?
Thanks

No. If it were 2.15 instead of 2.625, then we'd get $$\frac{x}{y}=2.15=2\frac{3}{20}=2+\frac{3}{20}$$, and in this case r would need to be a multiple of 3, not necessarily a multiple of 5.
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This post by VeritasKarishma explains it perfectly.
Math Expert
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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I think this is a high-quality question and I agree with explanation. Can anyone pls tell me how to convert decimals into improper fractions?
Math Expert
Joined: 02 Sep 2009
Posts: 93417
Own Kudos [?]: 626038 [0]
Given Kudos: 81940