Gmatprep550 wrote:
Hi
Bunuel,
chetan2uI am not aware about following rule, could you please elaborate it little.
"If both \(x + y\) and \(x - y\) are divisible by 3 then \(x + y + x - y = 2x\) is also divisible by 3"
Essentially, since both x + y and x - y are multiples of 3, their sum and their difference will also be multiples of 3.
WHEN THE SUM OR THE DIFFERENCE OF NUMBERS IS A MULTIPLE OF AN INTEGER1.
If integers \(a\) and \(b\) are both multiples of some integer \(k>1\) (divisible by \(k\)), then their sum and difference will also be multiples of \(k\) (divisible by \(k\)):Example: \(a=6\) and \(b=9\), both divisible by 3 ---> \(a+b=15\) and \(a-b=-3\), again both divisible by 3.
2.
If out of integers \(a\) and \(b\), one is a multiple of some integer \(k>1\) and the other is not, then their sum and difference will NOT be multiples of \(k\) (divisible by \(k\)):Example: \(a=6\), divisible by 3, and \(b=5\), not divisible by 3 ---> \(a+b=11\) and \(a-b=1\), neither is divisible by 3.
3.
If integers \(a\) and \(b\) both are NOT multiples of some integer \(k>1\) (divisible by \(k\)), then their sum and difference may or may not be multiples of \(k\) (divisible by \(k\)):Example: \(a=5\) and \(b=4\), neither is divisible by 3 ---> \(a+b=9\), is divisible by 3, and \(a-b=1\), is not divisible by 3;
OR: \(a=6\) and \(b=3\), neither is divisible by 5 ---> \(a+b=9\) and \(a-b=3\), neither is divisible by 5;
OR: \(a=2\) and \(b=2\), neither is divisible by 4 ---> \(a+b=4\) and \(a-b=0\), both are divisible by 4.
For more on this check:
5. Divisibility/Multiples/Factors
For other subjects:
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