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Re: M21-01 [#permalink]
filipTGIM wrote:
Or you can just find a fraction that has the least difference between numerator and denominator.


Can you please explain the concept behind this approach.
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Re: M21-01 [#permalink]
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Randude wrote:
filipTGIM wrote:
Or you can just find a fraction that has the least difference between numerator and denominator.


Can you please explain the concept behind this approach.


Hello Randude

\(\frac{9}{17}\), \(\frac{31}{61}\), \(\frac{41}{81}\)

We can see common thing in these fractions. Their nominator mutipled on 2 equal to denominator - 1
9*2 = 18 = 17-1
31*2 = 62 = 62-1
41*2 = 82 = 82-1

so 9/17 --> 17/2 = 8.5 this number on 0.5 less than 9 and we can write this fraction as half of 17 + 0.5 divide by 17 --> 1/2 + 0.5/17
so 31/61 --> 61/2 = 30.5 this number on 0.5 less than 31 and we can write this fraction as half of 61 + 0.5 divide by 61 --> 1/2 + 0.5/61
so 41/81 --> 81/2 = 40.5 this number on 0.5 less than 41 and we can write this fraction as half of 81 + 0.5 divide by 81 --> 1/2 + 0.5/81
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Re: M21-01 [#permalink]
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Multiplying \(\frac{9}{17}\) with 2 gives\(\frac{18}{34}\)
which can be written as\(\frac{17}{34}\)+ \(\frac{1}{34}\)
that gives us\(\frac{1}{2}\) + \(\frac{0.5}{17}\)

same way it is for \(\frac{31}{61}\)--> \(\frac{62}{61*2}\)= \(\frac{61}{61*2} + \frac{1}{61*2}\) = \(\frac{1}{2} + \frac{0.5}{61}\)

Hope it is clear now :)
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Re: M21-01 [#permalink]
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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Re: M21-01 [#permalink]
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