Farina wrote:
Bunuel wrote:
apple08 wrote:
need great help to correct my steps/understanding:
I need to choose one of crust with 4 toppings.
so I need to choose 1 from 2 and 4 toppings from 5:
my work is as follows:
2/1! multiply 5x4x3x2 / 4!
= 2 / 1 x 5x4x3x2/4x3x2x1
= 2 x 5
= 10 choices
why my answer is wrong, need great help
is cheese and regular is also part of the equation.
Many thanks
There is one more piece of information:
Mario's offers very pizza in extra-cheese as well as regular.
Mario's Pizza has two choices of crust: deep dish and thin-and-crispy. The restaurant also has a choice of 5 toppings: tomatoes, sausage, peppers, onions, and pepperoni. Finally, Mario's offers very pizza in extra-cheese as well as regular. If Linda's volleyball team decides to order a pizza with four toppings, how many different choices do the teammates have at Mario's Pizza? Mario's Pizza:
2 choices of crust.
5 choices of toppings.
2 choices of cheese (extra-cheese or regular).
Linda decides to order a pizza with four toppings.
How many 4-topping pizzas are possible from 5? \(C^4_5=5\). But the pizza can have 2 different crusts and two different cheese, therefore the final answer is 5*2*2 = 20.
Hi,
Can you please tell me when do we have to use Combination Formula and when simple multiplication? Like in this case, I applied the formula 2C1 * 5C4 * C1
whereas its just simple multiplication
Question:Mario's Pizza has two choices of crust: deep dish and thin-and-crispy. The restaurant also has a choice of 5 toppings: tomatoes, sausage, peppers, onions, and pepperoni. Finally, Mario's offers very pizza in extra-cheese as well as regular. If Linda's volleyball team decides to order a pizza with four toppings, how many different choices do the teammates have at Mario's Pizza?
Write in simple terms what you need to do:
You need to
choose 1 out of the 2 crusts AND choose 4 of the 5 toppings AND Choose one of the two cheese variantsNow write the value of each part in bold:
choose 1 out of the 2 crusts = 2c1
choose 4 of the 5 toppings = 5c4
choose one of the two cheese variants = 2c1
(Note: there is no step where you need to arrange anything)
Now, remember that
AND refers to multiplication;
OR refers to additionThus, our answer:
You need to
choose 1 out of the 2 crusts AND choose 4 of the 5 toppings AND Choose one of the two cheese variants= \(2c1 * 5c4 * 2c1\)
= \(2 * 5 * 2\)
= \(20\)
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