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Re: 3 girls and 3 boys sit down in in the row of 7 chairs. If [#permalink]
I am slightly confused by the approach given above. Let us assume there is 1 girl and 1 boy and 3 seats.

This provides 6 arrangements

_gb
_bg
b_g
g_b
bg_
gb_

For this the answer should be 1!*P(3,2)=6. Similarly according to me the answer for original question should be 3!*P(4,3) = 144
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Re: 3 girls and 3 boys sit down in in the row of 7 chairs. If [#permalink]
I think it is 2*7*3!*3!

If we take the arrangement: bgbgbg_
there are 7 choices for "_"

Also if we take gbgbgb_, there are 7 choices for the "_"

And for each of the two cases above, there are 3!*3! arrangements for boys and girs

Total choices = 2*7*3!*3!

OA please?
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Re: 3 girls and 3 boys sit down in in the row of 7 chairs. If [#permalink]
I am pathetic at combos, can someone tell me why we are multiplying by 7.
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Re: 3 girls and 3 boys sit down in in the row of 7 chairs. If [#permalink]
shahnandan wrote:
I am pathetic at combos, can someone tell me why we are multiplying by 7.


because of 1 empty chair that can be at 7 different places



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