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Concentration: Tuck,Cornell,Duke
 Q47  V20 GMAT 2: 560  Q45  V22
WE 1: 4.6 years Exp IT prof
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Manager
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Joined: 20 Apr 2010
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Concentration: Tuck,Cornell,Duke
 Q47  V20 GMAT 2: 560  Q45  V22
WE 1: 4.6 years Exp IT prof
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Manager
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Manager
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Joined: 20 Apr 2010
Posts: 169
Own Kudos [?]: 67 [1]
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Concentration: Tuck,Cornell,Duke
 Q47  V20 GMAT 2: 560  Q45  V22
WE 1: 4.6 years Exp IT prof
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Re: Probability Basics Rules & Questions (43) [#permalink]
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Let us make this post Nightmare for Probability Questions and heavens for people afraid of it.....

I will work hard you will work hard but Together we will definitely Succeed
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Re: Probability Basics Rules & Questions (43) [#permalink]
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Hey Qweert I am adding this doc to my initial post so we have everything in the main post
I hope you don't have any issue...!!!
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Re: Probability Basics Rules & Questions (43) [#permalink]
thanks a lot for this! probability for me was really confusing and your notes were a great help for my PE Exam review! ;)
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Re: Probability Basics Rules & Questions (43) [#permalink]
good questions, but I'll be careful with the provided answers and the questions wording. number 4 for example. How many 3-digit numbers satisfy the following conditions: The first digit is different from zero and the other digits are all different from each other?
in GMAT when you say and the other digits ( it means the 1st digit is not included). Similarly, are all different from each other came after "the other digits" so only the two remaining digits are different from each others. note that the word all here is wrong as "all" should indicates more than 2.
Also the 1st digit means the 1st digit from the right and not vice versa.

if I was to answer this question, my answer will be as following:
1st digit can only takes 9. no condition
2nd &3rd:
2nd digit can take 10 (0-9)
3rd can take only 9 (1-9) since zero won't make the number 3 digits.
from the 2nd &3rd digits you need to subtract the similar numbers which is 9 (1-9) since zero can only be assigned to the 2nd digit.

so now you have 1st(9 options) * 2nd&3rd(9x10-9)=81
answer is 9*81=729
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Re: Probability Basics Rules & Questions (43) [#permalink]
Number.37

there is a scenario not taken into account, 4th and 5th digit from the left equal each others. this should be added to the answer
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Re: Probability Basics Rules & Questions (43) [#permalink]
This question set has the answers typed out wrong. You must read the explanation to get the right answer choice rather than simply reading the letter mentioned in the document...
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Re: Probability Basics Rules & Questions (43) [#permalink]
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For other Probability issues, be sure to check out the detailed discussion I have here: https://privategmattutor.london/gmat-probability-resources-articles-books-and-videos/
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Re: Probability Basics Rules & Questions (43) [#permalink]
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