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Re: S96-14 [#permalink]
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Another way is finding the relation between x & y:

g(x,y) = m(x,y)
-> square both sides we have: \(xy = (x+y)^2/4\)
-> \(4xy = x^2+y^2 + 2xy\)
-> \(x^2+y^2-2xy = 0\)
->\((x-y)^2 = 0\)
-> \(x=y\)

-> answer D
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Re: S96-14 [#permalink]
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I think this is a poor-quality question and I agree with explanation. The "of" in the last line just before h(x,y) should be omitted.
Other wise the meaning of the question changes.
It should be: For which of the following pairs of values for x and y is g(x,y) equal to THE ARITHMETIC MEAN h(x,y) and m(x,y).
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Re: S96-14 [#permalink]
Hientran48 wrote:
Another way is finding the relation between x & y:

g(x,y) = m(x,y)
-> square both sides we have: \(xy = (x+y)^2/4\)
-> \(4xy = x^2+y^2 + 2xy\)
-> \(x^2+y^2-2xy = 0\)
->\((x-y)^2 = 0\)
-> \(x=y\)

-> answer D



Hi, the question asks (x,y) for which: g(x,y) = m(h(x,y),m(x,y)).
What you have solved algebraically is g(x,y) = m(x,y).

Using the process of elimination we can clearly remove A & E as they have \sqrt{2} in the g(x,y) whereas RHS will never have a square root as its simple addition of integers and their reciprocals.
B is eliminated because square root is not defined.
Of the remaining two, just plug any value and you'll have the answer as D.
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Re: S96-14 [#permalink]
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Bunuel wrote:
The harmonic mean of two numbers \(x\) and \(y\), symbolized as \(h(x, y)\), is defined as 2 divided by the sum of the reciprocals of \(x\) and \(y\), whereas the geometric mean \(g(x, y)\) is defined as the square root of the product of \(x\) and \(y\) (when this square root exists), and the arithmetic mean \(m(x, y)\) is defined as \(\frac{x + y}{2}\). For which of the following pairs of values for \(x\) and \(y\) is \(g(x, y)\) equal to the arithmetic mean of \(h(x, y)\) and \(m(x, y)\)?

A. \(x = -2\), \(y = -1\)
B. \(x = -1\), \(y = 2\)
C. \(x = 2\), \(y = 8\)
D. \(x = 8\), \(y = 8\)
E. \(x = 8\), \(y = 64\)



Geometric mean of x and y = root(xy)
Arithmetic mean of x and y = (x+y)/2
Harmonic mean of x and y = 2xy/(x+y)

We can try to solve this using algebra (very complicated) or try to solve using the options.

Let us now use a simple piece of information:

If the numbers x and y are equal, the geometric mean, arithmetic mean and harmonic mean are equal to one another and also equal to the numbers themselves.
(Note: If x and y are unequal, we have: AM > GM > HM)

Keeping this is in mind, if we check the options, we see that Option D has both numbers equal (= 8)
Thus, AM, GM and HM for the numbers x = y = 8 would also be 8
Thus, the Arithmetic Mean of the Geometric mean and Harmonic mean would also be 8

Thus, the correct answer is OPTION D
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Re: S96-14 [#permalink]
Since the equation is too complicated with square root and reciprocal, try the most simple pair of x and y, which is x=y=8. that we can simplify the equation. => answer D :lol: :lol:
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