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Bunuel, I do not understand the explanation. I got median between 10-11th students median range of 20-29 pages. I lost you from there....request an explanation if possible to help me understand
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Bunuel, I do not understand the explanation. I got median between 10-11th students median range of 20-29 pages. I lost you from there....request an explanation if possible to help me understand

A. In order to to minimize the # of writings which fall in the range median-6 and median+6 pages we should move as many writing as far as possible from the median. As the median is between 20-29 pages long (the third group) then move 4 students writings from this group to its lowest limit (20) and move all 7 students writings from the 4th group to its highest limit (39). Next, if 2 other students from the third group wrote 29 pages each, then the median would be 29, and only those two students will fall in the range from 29-6=23 and 29+6=35. Total: 2.

B. In order to to maximize the # of writings which fall in the range median-6 and median+6 pages we should move as many writing as close as possible from the median. The same here: move all 4 students writings from the 2nd group to its highest limit (19), move all 7 students writings from the 4th group to its lowest (30). Next, make the median so that median-6<19 (in order 4 students from the 2nd group to fall in the range) and median+6>30 (in order 7 students from the 4th group to fall in the range), which basically means that the median should be (19+30)/2=24.5. So, 10th and 11th students form the third group should write 24 and 25 pages (obviouslyall other students from this group will also be in the range). Total: 4+6+7=17.

Hope it's clear.
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Sorry Bunuel, I still cannot get there. Your explanation is still not clear to me. I am very weak in statistics, if you could please break it down a bit more, perhaps I will get there. Thanks in advance
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Sorry Bunuel, I still cannot get there. Your explanation is still not clear to me. I am very weak in statistics, if you could please break it down a bit more, perhaps I will get there. Thanks in advance

Can you please specify what part didn't you get?

Check similar questions to practice:
5-peices-of-wood-have-an-average-length-of-124-inches-and-123513.html
in-a-class-of-30-students-2-students-did-not-borrow-any-101980.html
set-r-contains-five-numbers-that-have-an-average-value-of-102087.html
three-boxes-of-supplies-have-an-average-arithmetic-mean-105819.html
the-average-arithmetic-mean-of-the-5-positive-integers-k-107059.html
if-the-average-of-5-positive-integers-is-40-and-the-127038.html

Hope it helps.
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I tried to calculate median using cumulative frequency and got 27.333 + - 6 => 21.3 and 33.3.

Using this range i got 0 and 13 answer.

Attachment:
median.jpg
median.jpg [ 54.4 KiB | Viewed 25865 times ]

Is this method applicable to this question ? or I am using a wrong method please help to verify ?

Thanks.
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I tried to calculate median using cumulative frequency and got 27.333 + - 6 => 21.3 and 33.3.

Using this range i got 0 and 13 answer.

Attachment:
median.jpg

Is this method applicable to this question ? or I am using a wrong method please help to verify ?

Thanks.

I am not sure what you have done here and why. How did you get a value for median? The median can take various different values. Also median is not a range or two points (21.3 and 33.3 that you obtained). Median of a data set is a single value. Are you somehow using Standard Deviation here?
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Hi Karishma,

I found this formula to calculate median for data defined in intervals.
Refer following link scroll down to median's formula.
https://mba-lectures.com/statistics/desc ... -data.html

I am just doing plus minus 6 pages to the median page count.
In this range I can keep minimum 0 seniors and maximum all 13 seniors.

Regards
PiyushK
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Hi Karishma,

I found this formula to calculate median for data defined in intervals.
Refer following link scroll down to median's formula.
https://mba-lectures.com/statistics/desc ... -data.html

I am just doing plus minus 6 pages to the median page count.
In this range I can keep minimum 0 seniors and maximum all 13 seniors.

Regards
PiyushK

The two concepts are different. In simple terms, the method you used is used to "best guess" the value of the median. Say, we only have the data of the graph and we need to guess the value of the median, then we can use that method. Actually, the value of the median might be much different. This question does not make you guess the value of the median. It says that the value can vary and asks for the case where you will get least/most members. It asks you how you should allot the pages so that you get the least/most value.
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sdas
Bunuel, I do not understand the explanation. I got median between 10-11th students median range of 20-29 pages. I lost you from there....request an explanation if possible to help me understand

A. In order to to minimize the # of writings which fall in the range median-6 and median+6 pages we should move as many writing as far as possible from the median. As the median is between 20-29 pages long (the third group) then move 4 students writings from this group to its lowest limit (20) and move all 7 students writings from the 4th group to its highest limit (39). Next, if 2 other students from the third group wrote 29 pages each, then the median would be 29, and only those two students will fall in the range from 29-6=23 and 29+6=35. Total: 2.

B. In order to to maximize the # of writings which fall in the range median-6 and median+6 pages we should move as many writing as close as possible from the median. The same here: move all 4 students writings from the 2nd group to its highest limit (19), move all 7 students writings from the 4th group to its lowest (30). Next, make the median so that median-6<19 (in order 4 students from the 2nd group to fall in the range) and median+6>30 (in order 7 students from the 4th group to fall in the range), which basically means that the median should be (19+30)/2=24.5. So, 10th and 11th students form the third group should write 24 and 25 pages (obviouslyall other students from this group will also be in the range). Total: 4+6+7=17.

Hope it's clear.

Hi Bunuel,
I know the median length is the average length of the 10th and 11th theses, but in the group where all of the 6 theses have 20-29 pages each, the 10th and the 11th theses are in the middle in terms of their lengths, therefore, given both 10th and 11th theses have 29 pages, the 8th and 9th theses in the 20-29 group have 22 pages each , and all of the 7 theses in the 30-39 group have 36 pages, I think the least number of the seniors writing theses satisfying the length within the range is 4, rather than 2, because the length of the 12th and 13th theses in the 20-29 group cannot be shorter than the 10th and 11th theses in the same group. Am I right? Thank you.
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Bunuel
sdas
Bunuel, I do not understand the explanation. I got median between 10-11th students median range of 20-29 pages. I lost you from there....request an explanation if possible to help me understand

A. In order to to minimize the # of writings which fall in the range median-6 and median+6 pages we should move as many writing as far as possible from the median. As the median is between 20-29 pages long (the third group) then move 4 students writings from this group to its lowest limit (20) and move all 7 students writings from the 4th group to its highest limit (39). Next, if 2 other students from the third group wrote 29 pages each, then the median would be 29, and only those two students will fall in the range from 29-6=23 and 29+6=35. Total: 2.

B. In order to to maximize the # of writings which fall in the range median-6 and median+6 pages we should move as many writing as close as possible from the median. The same here: move all 4 students writings from the 2nd group to its highest limit (19), move all 7 students writings from the 4th group to its lowest (30). Next, make the median so that median-6<19 (in order 4 students from the 2nd group to fall in the range) and median+6>30 (in order 7 students from the 4th group to fall in the range), which basically means that the median should be (19+30)/2=24.5. So, 10th and 11th students form the third group should write 24 and 25 pages (obviouslyall other students from this group will also be in the range). Total: 4+6+7=17.

Hope it's clear.

Hi Bunuel,
I know the median length is the average length of the 10th and 11th theses, but in the group where all of the 6 theses have 20-29 pages each, the 10th and the 11th theses are in the middle in terms of their lengths, therefore, given both 10th and 11th theses have 29 pages, the 8th and 9th theses in the 20-29 group have 22 pages each , and all of the 7 theses in the 30-39 group have 36 pages, I think the least number of the seniors writing theses satisfying the length within the range is 4, rather than 2, because the length of the 12th and 13th theses in the 20-29 group cannot be shorter than the 10th and 11th theses in the same group. Am I right? Thank you.

No, you are not right. Consider example below:

{0} {10, 10, 10, 10} {20, 20, 20, 20, 29, 29} {39, 39, 39, 39, 39, 39, 39} {40, 40}

1st group: 1 student wrote between 0-9 pages;
2nd group: 4 students wrote between 10-19 pages;
3rd group: 6 students wrote between 20-29 pages;
4th group: 7 students wrote between 30-39 pages;
5th group: 2 students wrote between 40-49 pages.

Hope it helps.
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Hello,

Can somebody explain how median of 10 and 11 fall into 6 students' pages? if we list students as following:
1 student - 0-9 pages
2 students - 40-49 pages
7 students - 30-39 pages
4 students - 10-19 pages
6 students - 20-29 pages
then, median of 10-11 students won't correspond to 20-29 pages.
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Hello,

Can somebody explain how median of 10 and 11 fall into 6 students' pages? if we list students as following:
1 student - 0-9 pages
2 students - 40-49 pages
7 students - 30-39 pages
4 students - 10-19 pages
6 students - 20-29 pages
then, median of 10-11 students won't correspond to 20-29 pages.

The median of a set with even number of elements is the average of two middle numbers when arranged in ascending or descending order.

There are total of 20 students.
1st group: 1 student wrote between 0-9 pages, say 1 page each;
2nd group: 4 students wrote between 10-19 pages, say 10 pages each;
3rd group: 6 students wrote between 20-29 pages, say 20 pages each;
4th group: 7 students wrote between 30-39 pages, say 30 pages each;
5th group: 2 students wrote between 40-49 pages, say 40 pages each.

{1, 10, 10, 10, 10, 20, 20, 20, 20, 20, 20, 30, 30, 30, 30, 30, 30, 30, 40, 40}.

As you can see, the median length would be the average of 10th and 11th students writings. Both, 10th and 11th students are in the third group, so both these student wrote between 20 and 29 pages (so the median will be between 20 and 29).
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The 2022 GMAT also can get these kind of questions in PS ?
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