Last visit was: 26 Apr 2024, 04:36 It is currently 26 Apr 2024, 04:36

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
Math Expert
Joined: 02 Sep 2009
Posts: 92929
Own Kudos [?]: 619142 [1]
Given Kudos: 81609
Send PM
Most Helpful Reply
Math Expert
Joined: 02 Sep 2009
Posts: 92929
Own Kudos [?]: 619142 [0]
Given Kudos: 81609
Send PM
General Discussion
BSchool Moderator
Joined: 08 Dec 2013
Posts: 686
Own Kudos [?]: 516 [0]
Given Kudos: 227
Location: India
Concentration: Nonprofit, Sustainability
Schools: ISB '23
GMAT 1: 630 Q47 V30
WE:Operations (Non-Profit and Government)
Send PM
GMAT Club Legend
GMAT Club Legend
Joined: 03 Oct 2013
Affiliations: CrackVerbal
Posts: 4946
Own Kudos [?]: 7628 [1]
Given Kudos: 215
Location: India
Send PM
Re: The twelve numbers shown represent, the ages, in years, of the twelve [#permalink]
1
Kudos
This a perfect question that we can use the concept of maximization and minimization. There are three things to keep in mind while solving questions related to the median :

1. By definition, the median is the middle value in a list of numbers arranged in ascending or descending order.
2. The arrangement is always key to solving questions related to the median.
3. On questions where we have a list of elements with many variables, maximization and minimization is the best way to proceed.

Now lets jump into the solving of the question.

We have the list x, x, x, x, 8, 8, 8, 8, 12, 12, 11,y. Since the data here are of ages, x and y have to be integers.

Statement 1 : x = 10

Arranging the elements in ascending order we get, 8, 8, 8, 8, 10, 10, 10, 10, 11, 12, 12, y.

Now let us think about the max and min values of y. If y >= 12, then the max median will be 10. If y <= 12, then the list now becomes y, 8, 8, 8, 8, 10, 10, 10, 10, 11, 12, 12. Again, the min median will be 10. Sufficient.

Statement 2 : y = 13

Arranging the elements in ascending order we get, x, x, x, x, 10, 10, 10, 10, 11, 12, 12, 13.

If x<= 10, the list will be as above and then the minimum median is 10, but if x >=13, then the list will be 10, 10, 10, 10, 11, 12, 12, 13, x, x, x, x. In this case the max median will be 12. So the median here can be any value from 10 to 12. Insufficient.

Hope this helps!
Aditya
BSchool Moderator
Joined: 08 Dec 2013
Posts: 686
Own Kudos [?]: 516 [0]
Given Kudos: 227
Location: India
Concentration: Nonprofit, Sustainability
Schools: ISB '23
GMAT 1: 630 Q47 V30
WE:Operations (Non-Profit and Government)
Send PM
Re: The twelve numbers shown represent, the ages, in years, of the twelve [#permalink]
AdityaCrackVerbal wrote:
This a perfect question that we can use the concept of maximization and minimization. There are three things to keep in mind while solving questions related to the median :

1. By definition, the median is the middle value in a list of numbers arranged in ascending or descending order.
2. The arrangement is always key to solving questions related to the median.
3. On questions where we have a list of elements with many variables, maximization and minimization is the best way to proceed.

Now lets jump into the solving of the question.

We have the list x, x, x, x, 8, 8, 8, 8, 12, 12, 11,y. Since the data here are of ages, x and y have to be integers.

Statement 1 : x = 10

Arranging the elements in ascending order we get, 8, 8, 8, 8, 10, 10, 10, 10, 11, 12, 12, y.

Now let us think about the max and min values of y. If y >= 12, then the max median will be 10. If y <= 12, then the list now becomes y, 8, 8, 8, 8, 10, 10, 10, 10, 11, 12, 12. Again, the min median will be 10. Sufficient.

Statement 2 : y = 13

Arranging the elements in ascending order we get, x, x, x, x, 10, 10, 10, 10, 11, 12, 12, 13.

If x<= 10, the list will be as above and then the minimum median is 10, but if x >=13, then the list will be 10, 10, 10, 10, 11, 12, 12, 13, x, x, x, x. In this case the max median will be 12. So the median here can be any value from 10 to 12. Insufficient.

Hope this helps!
Aditya


Hello Aditya, nice to see you on the gmatclub & thank you for the precise explanation.

AdityaCrackVerbal
GMAT Club Bot
Re: The twelve numbers shown represent, the ages, in years, of the twelve [#permalink]
Moderator:
Math Expert
92929 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne